Answer:
The length of Ann's toy fish is 12 inches; the length of Carol's toy fish is 17 inches; and the length of Liz's toy fish is 33 inches.
Step-by-step explanation:
Let's say Carol's fish is c inches long, Ann's is a inches long, and Liz's is l inches long. Then:
c = 5 + a
l = 9 + 2a
a = 12
Plug 12 in for a to find c and l:
c = 5 + a = 5 + 12 = 17 inches
l = 9 + 2a = 9 + 2 * 12 = 9 + 24 = 33 inches
Thus:
The length of Ann's toy fish is 12 inches; the length of Carol's toy fish is 17 inches; and the length of Liz's toy fish is 33 inches.
Answer: The mean and standard deviation are 567.2 and 89.88 resp.
Step-by-step explanation:
Since we have given that
For 370 parts per million = 7% = 0.07
For 440 parts per million = 10% = 0.10
For 550 parts per million = 49% = 0.49
For 670 parts per million = 34% = 0.34
So, Mean of the carbon dioxide atmosphere for these trees would be
![E[x]=370\times 0.07+440\times 0.1+550\times 0.49+670\times 0.34=567.2](https://tex.z-dn.net/?f=E%5Bx%5D%3D370%5Ctimes%200.07%2B440%5Ctimes%200.1%2B550%5Ctimes%200.49%2B670%5Ctimes%200.34%3D567.2)
And
![E[x^2]=370^2\times 0.07+440^2\times 0.1+550^2\times 0.49+670^2\times 0.34=329794](https://tex.z-dn.net/?f=E%5Bx%5E2%5D%3D370%5E2%5Ctimes%200.07%2B440%5E2%5Ctimes%200.1%2B550%5E2%5Ctimes%200.49%2B670%5E2%5Ctimes%200.34%3D329794)
So, Variance would be
![Var\ x=E[x^2]-E[x]^2=329794-567.2^2=8078.16](https://tex.z-dn.net/?f=Var%5C%20x%3DE%5Bx%5E2%5D-E%5Bx%5D%5E2%3D329794-567.2%5E2%3D8078.16)
So, the standard deviation would be

Hence, the mean and standard deviation are 567.2 and 89.88 resp.
Answer:
(-6/7)^0=1
-(2)^0=-1
Step-by-step explanation:
hope it helped
can I have a brainliest please i really need that
<span>the probability of an event and the probability of its complement add up to 1
because the total events are the even it self and its compliment, so its probability equal to 1 because these are all the possible events that will occur. for example a coin toss, an event head will happen 0.5, and its complement is tails which will also happens 0.5</span>