Answer:
Road C is 1.5 mi east of Road A
Step-by-step explanation:
we know that
Road B is 4.6 mi east of Road A
Road C is 3.1 mi west of Road B
so
Road C is between Road A and Road B
AB=4.6 miles
CB=3.1 miles
AB=AC+CB
Solve for AC
AC=AB-CB
AC=4.6-3.1=1.5 miles
therefore
Road C is 1.5 mi east of Road A
Answer/Step-by-step explanation:
I did the work on paper:
Answer:
x=2
Step-by-step explanation:
logx (2x)^3 = 6
We can rewrite without the exponent
3 logx (2x) = 6
Divide by 3
3/3 logx (2x) = 6/3
logx (2x) = 2
Raise each side to the base x
x^ logx (2x) =x^ 2
2x = x^2
Subtract 2x from each side
2x-2x = x^2 -2x
0 = x^2 -2x
Factor an x
0 = x(x-2)
Using the zero product property
x =0 x-2 =0
x =0 x=2
We cannot have a base of 0, so x cannot equal 0
x=2
No it is not because 15 out of 30 is half but 12 out of 20 is more than half
