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Sedbober [7]
3 years ago
6

BRAINLIEST!!!! Identify the equation of the translated graph in general form

Mathematics
2 answers:
RUDIKE [14]3 years ago
8 0

Answer:

Hyperbola:

x^2-y^2-8x+6y-1=0

Step-by-step explanation:

the given hyperbola has equation:

x^2-y^2=8

This is an equation of a hyperbola centered at the origin.

This hyperbola is translated so its center is now at T(4,3)

(x-4)^2-(y-3)^2=8

We expand to get:

x^2-8x+16-(y^2-6y+9)=8

x^2-8x+16-y^2+6y-9=8

x^2-8x-y^2+6y+7=8

x^2-8x-y^2+6y+7-8=0

x^2-y^2-8x+6y-1=0

xeze [42]3 years ago
6 0

Answer:

Its B

Step-by-step explanation:

it just is lol

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Parts being manufactured at a plant are supposed to weigh 65 grams. Suppose the distribution of weights has a Normal distributio
andrew-mc [135]

Answer:

0.64%.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 75 grams and a standard deviation of 22 grams.

This means that \mu = 75, \sigma = 22

Sample of 144:

This means that n = 144, s = \frac{22}{\sqrt{144}} = 1.8333

More than 80 or less than 70:

Both are the same distance from the mean, so we find one probability and multiply by 2.

The probability that it is less than 70 is the pvalue of Z when X = 70. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{70 - 75}{1.8333}

Z = -2.73

Z = -2.73 has a pvalue of 0.0032

2*0.0032 = 0.0064.

0.0064*100% = 0.64%

The probability is 0.64%.

3 0
3 years ago
Simplify the radical expression sqrt 7+3 sqrt 7
Alika [10]
4\sqrt{7}

This is because there is an imaginary 1 in front of the first sqrt. 
6 0
3 years ago
Read 2 more answers
A plane flew 2,190 kilometers from Chicago to Flagstaff. Another plane flew 2,910 kilometers from Chicago to Oakland. How much f
DiKsa [7]
The answer is 720.hope it helps.
3 0
4 years ago
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How much<br> lemonade will<br> each person get<br> if 4 people share <br> 1/2 gallon equally?
Charra [1.4K]
I’m pretty sure the answer would be 8 if u cut 4 in half 4 times
3 0
3 years ago
the point (4,0) lies on a circle with the center at the orgin. what is the area of the circle to the nearsest hundreth?
kvasek [131]

Answer:

50.27 units²

Step-by-step explanation:²

The standard equation of a circle with center at the origin is x² + y² = r², where r is the radius.  Substituting 4 for x and 0 for y yields 4² + 0² = r², so we see immediately that r = 4 units.

The formula for the area of a circle is A = πr².

Here, with r = 4, the area is A = π(4 units)² = 16π units², or

50.27 units² to the nearest hundredth.

3 0
3 years ago
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