Question

BRAINLIEST!!!! Identify the equation of the translated graph in general form

Answer 1

Answer:

Hyperbola:

$x^2-y^2-8x+6y-1=0$

Step-by-step explanation:

the given hyperbola has equation:

$x^2-y^2=8$

This is an equation of a hyperbola centered at the origin.

This hyperbola is translated so its center is now at T(4,3)

$(x-4)^2-(y-3)^2=8$

We expand to get:

$x^2-8x+16-(y^2-6y+9)=8$

$x^2-8x+16-y^2+6y-9=8$

$x^2-8x-y^2+6y+7=8$

$x^2-8x-y^2+6y+7-8=0$

$x^2-y^2-8x+6y-1=0$

Answer 2

Answer:

Its B

Step-by-step explanation:

it just is lol