What is the median in the box plot?

Mathematics

2 answers:

Sergio039 [100]3 years ago

8 0

<h3>Answer: 76</h3>

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Explanation:

The median is the vertical line inside the boxplot. This vertical line is at 76.

The median does not have to be at the exact midpoint of the box, as it could be much closer to one of the edges. All that matters is the median is between Q1 and Q3

Q1 = left edge of the box

Q3 = right edge of the box

The min and max are the tips of the left and right whiskers respectively. This is when there are no outlier island points to either side.

Serjik [45]3 years ago

6 0

Answer:

Step-by-step explanation:

The median line in the middle of the box is at 76 (the number line is by 2's)

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Rachel was carpeting a square-shaped room. The area of the room was 165 square feet. Which of the answer choices shows the lengt

nekit [7.7K]

Answer: 13

Step-by-step explanation:

Area = 165

Area of square is :

Area = length × length

Let length be l

165 = l ^ 2

Square both side

l = sqrt(165)

l = 12.85

l = 13 to the nearest whole number

8 0

4 years ago

Inveres laplace transform (3s-14)/s^2-4s+8

Olenka [21]

Complete the square in the denominator.

$s^2 - 4s + 8 = (s^2 - 4s + 4) + 4 = (s-2)^2 + 4$

Rewrite the given transform as

$\dfrac{3s-14}{s^2-4s+8} = \dfrac{3(s-2) - 8}{(s-2)^2+4} = 3\times\dfrac{s-2}{(s-2)^2+2^2} - 4\times\dfrac{2}{(s-2)^2+2^2}$

Now take the inverse transform:

$L^{-1}_t\left\{3\times\dfrac{s-2}{(s-2)^2+2^2} - 4\times\dfrac{2}{(s-2)^2+2^2}\right\} \\\\ 3L^{-1}_t\left\{\dfrac{s-2}{(s-2)^2+2^2}\right\} - 4L^{-1}_t\left\{\dfrac{2}{(s-2)^2+2^2}\right\} \\\\ 3e^{2t} L^{-1}_t\left\{\dfrac s{s^2+2^2}\right\} - 4e^{2t} L^{-1}_t\left\{\dfrac{2}{s^2+2^2}\right\} \\\\ \boxed{3e^{2t} \cos(2t) - 4e^{2t} \sin(2t)}$