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Juli2301 [7.4K]
3 years ago
8

Give the equation pls

Mathematics
1 answer:
Sveta_85 [38]3 years ago
6 0

Answer: The equation of the line x + 3y = 9 can be written in the slope intercept form y = mx + c as . The slope of this line is . As the product of the slope of perpendicular lines is equal to -1, the slope of a line perpendicular to x + 3y = 9 is 3.

Step-by-step explanation:

ok im super sorry if this doesn't help I'm not partially skilled when it comes to this type of stuff and if it doesn't even relate to the question sorry qwq I really hoped it help and if it didnt just tell me and i can delete it

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Answer: A(3, -5)

B(6, -2)

C(9, -2)

Step-by-step explanation:

If we have a point (x, y), and we do a reflection over the axis y = a, then the only thing that will change in our point is the value of x.

Now, the distance between x and a must remain constant before and after the reflection.

so if x - a = d

then the new position of the point will be:

(a - d, y) = (2a - x, y).

I will use that relationship for the 3 points

A)

We start with the point (1, -5)

The reflection over y = -1 leaves.

The distance between 1 and -1 is = 1 - (-1) = 2.

Then the new point is (-1 - 2, -5) = (-3, -5)

Now we do a reflection over y = 1, so D = -3 - 1 = -2

Then the new point is:

A = (1 -(-2), -5) = (3, -5)

B) (2, -2)

Reflection over y = -1.

distance, d = 2 - (-1) = 3

the point is (-1 - 3, -2) = (-4, -2)

Now, a reflection over y = 1.

The distance is D = -4 - 1 = -5

The new point is (1 - (-5), 2) = (6, -2)

C) (5, -2)

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Distance: D = 5 - ( - 1) = 6

New point: (-1 - 6, -2) = (-7, -2)

Reflection over y = 1.

Distance D = -7 - 1 = -8

New point ( 1 - (-8), -2) = (9, -2)

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