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3 years ago

A 35 ounce bag of chips costs $4.99. What is the price per ounce?

Mathematics

1 answer:

Vika [28.1K]3 years ago

7 0

Answer:

The answer to the question provided is $7.01

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The length of line segment AD is 6.8 cm. The length of line segment AB is 3 cm. The length of line segment BC is 1.6 cm. Find th

saw5 [17]

Answer:

9.6

Step-by-step explanation:

This is a four side figure which is most likely to be a trapezium.So AD is the hypotenuse,AB is side (a),BC is the height and CD is side (b).

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2 years ago

An angle that measures 89 degrees is called?

mafiozo [28]

An acute angle is any angle that is below 90 degrees, so 89 degrees is an ancute angle

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2 years ago

Need help now please.

Anika [276]

8 is A
9 is D
10 is C
11 is B

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2 years ago

T-T help me I can't think

BartSMP [9]

Answer:

81 square inches

Step-by-step explanation:

area of a square= s^2

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2 years ago

Sec squared 55 - tan squared 55

sergejj [24]

<u>Answer: </u>

sec squared 55 – tan squared 55 = 1

<u>Explanation:</u>

Given, sec square 55 – tan squared 55

We know that,

$\sec \Theta=\frac{\text {hypotenuse}}{\text {base}}$

And,

$\tan \theta=\frac{\text { perpendicular }}{\text { base }}$

where Ө is the angle

Substituting the values

$\left(\frac{\text {hypotenuse}}{\text {base}}\right)^{2}-\left(\frac{\text { perpendicular }}{\text {base}}\right)^{2}$

Solving,

$\frac{(\text {hypotenuse})^{2}-(\text {perpendicular})^{2}}{(\text {base}) *(\text {base})}$

According to Pythagoras theorem,

$\text { (hypotenuse) }^{2}-\text { (perpendicular) }^{2}=(\text { base })^{2}$

Putting this in the equation;

squared 55 - tan squared 55 =

$\frac{(\text {hypotenuse})^{2}-(\text {perpendicular})^{2}}{(\text {base}) *(\text {base})}=\frac{(\text {base})^{2}}{(\text {base}) *(\text {base})}=1$

Therefore, sec squared 55 – tan squared 55 = 1

6 0

3 years ago