WORK:
34.3 - 11.8 = 22.5
ANSWER:
m = 22.5
So,
The answer is A. 22.5
Answer:
Step-by-step explanation:
16.0 you’re welcome anything 5 or over gets rounded up 4 is less
Than 5 so it gets rounded down
Answer:
2(x + 4) / 6(x² - 3x - 28)
Step-by-step explanation:
Area of a rectangle = length × width
Length = 2/(x² - 3x - 28)
Width = x² - 16/6x - 24
= (x + 4)(x - 4) / 6(x - 4)
= (x + 4) / 6
Area of a rectangle = length × width
= 2/(x² - 3x - 28) × (x + 4) / 6
= 2(x + 4) / (x² - 3x - 28)6
= 2(x + 4) / 6x² - 18x - 168
= 2(x + 4) / 6(x² - 3x - 28)
Area of a rectangle =
2(x + 4) / 6(x² - 3x - 28)
To solve this prolem you must apply the proccedue shown below:
1. You must apply the formula for calculate the volume of a rectangular prism and the formula for calculate the volume of a rectangular pyramid:
- Volume of the rectangular prism:
V1=lwh
Where l is the length, w i the width and h is the height
V1=(24 cm)(3 cm)(12 cm)
V1=864 cm^3
- Volume of the rectangular pyramid:
V2=lwh/3
Where l is the length, w is the width and h is the height
V2=(24 cm)(3 cm)(21 cm)/3
V2=504 cm^3
-The volume of the figure is:
Vt=V1+V2
Vt=1368 cm^3
The answer is: 1368 cm^3
Answer:
The number of teachers who teach physics n(P) = 12
Step-by-step explanation:
<u><em>Step(i):</em></u>-
Given that the number of teachers who teach mathematics or physics
n(MUP) = 20
Given that the number of teachers who teach mathematics
n(M) = 12
Given that the number of teachers who teach both mathematics and physics
n(M∩P) = 4
<u><em>Step(ii):-</em></u>
By using n(A∪B) = n(A) + n(B) - n(A∩B)
n(M∪P) = n(M) +n(P) - n(M∩P)
20 = 12 + n(P) - 4
20 -12 +4 = n(P)
n(P) = 12
<u><em>Final answer:-</em></u>
The number of teachers who teach physics n(P) = 12