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3 years ago

Last one i need help with these too

Mathematics

1 answer:

Licemer1 [7]3 years ago

5 0

Welcome HAHHAHAHAHAHAHAHHAHAHAHAHHAHAHA

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Gwar [14]

Answer:

Step-by-step explanation:

i think b and c i know a and d are wrong but hope it helps

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3 years ago

Came someone help me please

sleet_krkn [62]

Answer:

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3 years ago

Point A is located at negative 4 over 6 and point B is located at negative 1 over 6. What is the distance between points A and B

Luba_88 [7]

Take a picture of the problem

4 0

3 years ago

Citrus farmer who grows mandarin oranges finds that the diameters of mandarin oranges harvested on his farm follow a normal dist

SSSSS [86.1K]

Answer:

6.0520

Step-by-step explanation:

Given that:

Mean = 5.85

Standard deviation = 0.24

Let N denote the 80th percentile.

P(X < N) = 0.8

$P(Z < \dfrac{(N - 5.85)}{0.24}) = 0.8$

Using the Excel formula: = NORM.INV(0.8,5.85,0.24)

The 80th percentile for the diameters of mandarin oranges:

= 6.0520 (to 4 decimal place)

8 0

3 years ago

A road has a 10% grade, meaning increasing 1 unit of rise to every 10 units of run.

fenix001 [56]

The grade is the ratio of rise to run, i.e. the slope aka the tangent.

$\tan \theta = \dfrac{1}{10}$

$\theta = \arctan 0.1 \approx 5.711^\circ$

Answer: (a) 6 degrees

For part b, the road is the hypotenuse c of a right triangle whose tangent of the small angle is 1/10. The height h or rise is the side opposite the small angle.

$\sin\theta = \dfrac h c$

$h = c \sin \theta$

We could just take the sine of the angle we got but let's get it from the tangent exactly.

$\cos^2 \theta + \sin ^2 \theta = 1$

Dividing by squared cosine

$1 + \tan ^2 \theta = 1/\cos^2 \theta = 1/(1- \sin^2 \theta)$

$(1- \sin^2 \theta) = 1/(1 + \tan^2 \theta)$

$\sin^2 \theta = 1 - 1/(1 + \tan^2 \theta)$

$\sin^2 \theta = 1 - 1/(1 + (1/10)^2) = 1-1/(101/100) = 1/101$

$h = c \sin \theta = 2 \sqrt{1/101} \approx 0.199$

Answer: (b) Rise of 0.199 km

6 0

4 years ago