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ollegr [7]
3 years ago
14

Original price of a pen:$1.50tax:4%​

Mathematics
2 answers:
kkurt [141]3 years ago
6 0

Answer:

$1.56

Step-by-step explanation:

1.50 times 0.04 is 0.06

1.50+0.06

$1.56

fomenos3 years ago
4 0

Answer:

ANswer is $2.10.

Step-by-step explanation:

The tax is $.60 and you add that to $1.50.

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I AM GROOT I AM GROOT

Step-by-step explanation:

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2 years ago
I think it's either C or D but I'm not sure plzzz help me !?!?!?!
Dennis_Churaev [7]
Using th epythagorean theorem.

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3 0
3 years ago
How may different arrangements are there of the letters in ALASKA? 7 of 10 (5 complete) HW Score: 26.15% E Que The number of pos
Lubov Fominskaja [6]
<h2>Answer:</h2>

The number of possible arrangements is : 120

<h2>Step-by-step explanation:</h2>

We know that in order to find the different arrangements which are possible we need to use the method of permutation.

The arrangement of a given word is calculated as the ratio of the factorial of number of letters to the product of factorial of numbers the number of times each letter is repeating.

The word is given to be:

                    ALASKA

There are a total of 6 letters in the given word

Out of which a letter "A" is  repeating  3 times.

Hence, the number of arrangements possible are:

        =\dfrac{6!}{3!}\\\\\\=\dfrac{6\times 5\times 4\times 3!}{3!}\\\\\\=6\times 5\times 4\\\\\\=120

4 0
3 years ago
Michael has finished 25% of an art project that has taken
Nostrana [21]
It will take him 16 hours. Hope it helps
7 0
3 years ago
(x+5)(√ 1-x)<br> what is the product of this composite function?
Radda [10]

Answer:

x\sqrt{1-x}+5\sqrt{1-x}

Step-by-step explanation:

(x+5)(\sqrt{1-x} )\\\\=\left(\sqrt{1-x}\right)\left(x+5\right)\\\\\mathrm{Apply\:the\:distributive\:law}:\quad \:a\left(b+c\right)=ab+ac\\\\a=\left(\sqrt{1-x}\right),\:b=x,\:c=5\\\\=\left(\sqrt{1-x}\right)x+\left(\sqrt{1-x}\right)\times\:5\\\\=x\left(\sqrt{1-x}\right)+5\left(\sqrt{1-x}\right)\\\\\mathrm{Remove\:parentheses}:\quad \left(a\right)=a\\\\=x\sqrt{1-x}+5\sqrt{1-x}

6 0
3 years ago
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