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3 years ago

Drag and drop the symbols to enter the equation of the circle in standard form with center and radius given.

1 answer:

3 0

The standard equation of a circle with center C(a, b) and radius r is given by:

$(x-a)^2+(y-b)^2=r^2$

thus for C(a, b)=C(7, 5) and radius r=4, the equation is given by:

$(x-a)^2+(y-b)^2=r^2\\\\(x-7)^2+(y-5)^2=4^2$

Answer:

$(x-7)^2+(y-5)^2=4^2$

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Recall that a right triangle is a triangle with one right angle. One angle of a triangle measures 89.99°. Can the triangle be a

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Yes because the right triangle has a right angle which will equal to 90° you can place 89.99 to the nearest whole number which will give you a right angle.

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3 years ago

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Compare the numbers. Use >, =, or <

lesya692 [45]

Answer:

746.982 > 746.963

68.098 < 68.987

589.987 = 589.987

Step-by-step explanation:

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3 years ago

Graphic DesignWorks ships the t-shirts it makes in boxes that measure 20 in x 18 in x 15 in. The company rents a storage space t

ioda

Answer:

D) 1,036,800 boxes

Step-by-step explanation:

The volume of a box is ...

(20 in)(18 in)(15 in) = 5400 in^3

The volume of the storage space is ...

(300 ft)(240 ft)(45 ft) = 3,240,000 ft^3

Then the number of boxes that will fit in the storage space is ...

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8 0

3 years ago

A certain number of sixes and nines is added to give a sum of 126; if the number of sixes and nines is interchanged, the new sum

galina1969 [7]

Answer:

Original number of sixes = 6

Original number of nines = 10

Step-by-step explanation:

We are told in the question that:

A certain number of sixes and nines is added to give a sum of 126

Let us represent originally

the number of sixes = a

the number of nines = b

Hence:

6 × a + 9 × b = 126

6a + 9b = 126.....Equation 1

If the number of sixes and nines is interchanged, the new sum is 114.

For this second part, because it is interchanged,

Let us represent

the number of sixes = b

the number of nines = a

6 × b + 9 × a = 114

6b + 9a = 114.......Equation 2

9a + 6b = 114 .......Equation 2

6a + 9b = 126.....Equation 1

9a + 6b = 114 .......Equation 2

We solve using Elimination method

Multiply Equation 1 by the coefficient of a in Equation 2

Multiply Equation 2 by the coefficient of a in Equation 1

6a + 9b = 126.....Equation 1 × 9

9a + 6b = 114 .......Equation 2 × 6

54a + 81b = 1134 ........ Equation 3

54a + 36b = 684.........Equation 4

Subtract Equation 4 from Equation 3

= 45b = 450

divide both sides by b

45b/45 = 450/45

b = 10

Therefore, since the original the number of nines = b,

Original number of nines = 10

Also, to find the original number of sixes = a

We substitute 10 for b in Equation 1

6a + 9b = 126.....Equation 1

6a + 9 × 10 = 126

6a + 90 = 126

6a = 126 - 90

6a = 36

a = 36/6

a = 6

Therefore, the original number of sixes is 6

7 0

3 years ago