Question

Drag and drop the symbols to enter the equation of the circle in standard form with center and radius given.

Answer 1

The standard equation of a circle with center C(a, b) and radius r is given by:

$(x-a)^2+(y-b)^2=r^2$



thus for C(a, b)=C(7, 5)    and radius r=4, the equation is given by:

$(x-a)^2+(y-b)^2=r^2\\\\(x-7)^2+(y-5)^2=4^2$


Answer: 

$(x-7)^2+(y-5)^2=4^2$