Answer:
The nth term of an AP will be 27 -7n.
Step-by-step explanation:
First five terms of the Arthemetic Sequence is given to us , which is 26 , 19 , 12 , 5
Hence here Common Difference can be found by subtracting two consecutive terms . Here which is 19 - 26 = (-7) .
Here first term is 26 .
And the nth term of an AP is given by ,
★ T_n = a + ( n - 1) d
<u>Subst</u><u>ituting</u><u> respective</u><u> values</u><u> </u><u>,</u>
⇒ T_n = a + ( n - 1 )d
⇒ T_n = 26 + (n - 1)(-7)
⇒ T_n = 26 -7n+1
⇒ T_n = 27 - 7n
<h3>
<u>Hence </u><u>the</u><u> </u><u>nth</u><u> </u><u>term</u><u> of</u><u> an</u><u> </u><u>AP</u><u> </u><u>can</u><u> </u><u>be</u><u> </u><u>found </u><u>using </u><u>T_</u><u>n</u><u> </u><u>=</u><u> </u><u>2</u><u>7</u><u> </u><u>-</u><u> </u><u>7</u><u>n</u><u>. </u></h3>
Answer:
b-3>15b>18(18 infinity)
Step-by-step explanation:
Answer:
Ok so QR=10 because x=5 and the bisector I believe is LM :)
Step-by-step explanation:
Answer:
The revenue depends on the number of people n that purchases tickets, knowing that each ticket costs $30.00, the total revenue will be:
f(n) = $30.00*n
Now, we also know that the stadium is capable of seating a maximum of m fans, so the maximum possible value for n is m.
Now, for the function f(n), we have that:
The domain is the set of the possible values of n
The range is the set of the possible values of f(n).
We want to find the domain.
First, the minimum possible value of n is 0, the case where nobody purchases a ticket.
The maximum possible value of n is m, this is the case where the stadium is full.
Then the domain will be:
D= {n,m ∈ Z, 0 ≤ n ≤ m}
Where we imposed that n must be an integer number because n represents a whole quantity.
Answer:
5
Step-by-step explanation:
3(2)-1
6-1
5