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nlexa [21]
3 years ago
11

(b) A solid metal cone has radius 1.65 cm and slant height 4.70 cm.

Mathematics
1 answer:
Jlenok [28]3 years ago
4 0

Answer:

13.4

Step-by-step explanation:

πr2h

3

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Jillian and Dawn are playing a game of miniature golf. In this game, the score on a hole is the number of putts it takes to get
frozen [14]

Answer:

Step-by-step explanation:

Discussion

This should be answered with the mean. The lower the mean, the lower the  score it took to get the mean. So B is the answer.

4 0
2 years ago
- 5x - 2y &lt;6<br> y &gt;-x+1
butalik [34]

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i dont know im only in 7th

Step-by-step explanation:

teehee

5 0
2 years ago
A cylindrical soup can has a diameter of 3.6 in. and is 6.4 in. tall. Find the volume of the can.
arsen [322]
<h2>⚘Your Answer:------</h2>

<h3><u>Given</u><u> </u><u>Information</u><u>:</u></h3>

  • <u>Diameter of can</u>:- 3.6 cm
  • <u>Height of</u><u> </u><u>can</u><u>:</u><u>-</u> 6.4 cm

<h3><u>To</u><u> </u><u>Find</u><u> </u><u>Out</u><u>:</u></h3>

  • <u>Volume</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>Can</u><u>.</u>

<h3><u>Solution</u><u>:</u></h3>

Radius = (Diameter/2)

ㅤㅤㅤㅤ3.6 cm/2

ㅤㅤㅤㅤ1.8 cm

<u>So</u><u>,</u><u> </u><u>Radius</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>soup</u><u> </u><u>can</u><u> </u><u>is</u> 1.8 cm.

Volume øf cylinder = Volume øf can

Volume of cylinder = π r²h

(π = 22/7)

(r = radius = 1.8 cm)

(h = height = 6.4 cm

ㅤㅤㅤㅤㅤㅤㅤㅤㅤ= 22/7×(1.8 cm)²× 6.4 cm

ㅤㅤㅤㅤㅤㅤㅤㅤㅤ= 22/7× 3.24 cm² × 6.4 cm

ㅤㅤㅤㅤㅤㅤㅤㅤㅤ= 22/7 × 20.736 cm³

ㅤㅤㅤㅤㅤㅤㅤㅤㅤ= (456.192/7) cm³

ㅤㅤㅤㅤㅤㅤㅤㅤㅤ= 65.17 cm³

So, the Volume of the soup can is 65.17 cm³

ㅤㅤㅤㅤㅤㅤㅤㅤ⚘Thank You

7 0
2 years ago
For what value(s) of k is the linear system consistent? (Enter your answers as a comma-separated list.)
AleksAgata [21]

Answer:

Step-by-step explanation:

Given

6x_1-9x_2=8

9x_1+kx_2=-1

The given system is AX=B can be represented by

\begin{bmatrix}6 &-9 \\ 9 & k\end{bmatrix}\begin{bmatrix}x_1\\ x_2\end{bmatrix}=\begin{bmatrix}8\\ -1\end{bmatrix}

The given system is consistent when determinant of A is not equal to zero

|A|

|A|=6k-(-81)=6k+81

k\neq \frac{-27}{2}

i.e. system is consistent for all value of k except k=\frac{-27}{2}

R-\frac{-27}{2}

                 

4 0
3 years ago
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X^2-5x-14 
It is the correct answer I think
5 0
3 years ago
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