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just olya [345]
3 years ago
10

In a study of the accuracy of fast food​ drive-through orders, one restaurant had 34 orders that were not accurate among 371 ord

ers observed. Use a 0.01 significance level to test the claim that the rate of inaccurate orders is equal to​ 10%. Does the accuracy rate appear to be​ acceptable? Identify the null and alternative hypotheses for this test?
Mathematics
1 answer:
postnew [5]3 years ago
8 0

Answer:

The claim that he rate of inaccurate orders is equal to​ 10% is supported by statistical evidnece at 5% level

Step-by-step explanation:

Given that in a study of the accuracy of fast food​ drive-through orders, one restaurant had 34 orders that were not accurate among 371 orders observed.

Sample proportion p=0.092\\q=1-p = 0.908\\n = 371

H_0: p =0.10\\H_a: p \neq 0.10

(Two tailed test at 5% significance level)

p difference = 0.092-0.100\\=-0.0084

Std error if H0 is true = \sqrt{\frac{0.1(0.9)}{371} } \\=0.016

Test statistic Z = p diff/std error

=0.539

p value = 0.5899

Since p > 0.05 accept null hypothesis

The claim that he rate of inaccurate orders is equal to​ 10% is supported by statistical evidnece at 5% level

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photoshop1234 [79]
The net amount they raise is the amount they receive minus what they pay in expenses.

They receive:
$10,000 fixed amount in donations
$55 per person

They pay:
$15 per person

If there are x number of entries, they receive 55x from the entries.
Also, they pay 15x for the entries.

The net amount they raise is amount they receive min us amount they pay:

55x + 10,000 - 15x

which simplifies to

40x + 10,0000

They want to raise at least $55,000.
At least $55,000 means $55,000 or more.
They want to raise an amount greater than or equal to $55,000.

Now we write the inequality:

40x + 10,000 >= 55,000

Now we solve the inequality for x, the number of entries.

40x >= 45,000

x >= 1125

They must have 1125 or more race entries to raise $55,000.
6 0
4 years ago
At a restaurant, 5 of every 12 customers had a salad with their meal.
AnnZ [28]
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6 0
4 years ago
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An elevator starts on the 100th floor. It descends 4 floors every 10 seconds. At what floor will the elevator be 60 seconds afte
Artyom0805 [142]
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8 0
3 years ago
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After an antibiotic tablet is taken, the concentration of the antibiotic in the bloodstream is modelled by the function C(t)=8(e
Alexxx [7]

Answer:

the maximum concentration of the antibiotic during the first 12 hours is 1.185 \mu g/mL at t= 2 hours.

Step-by-step explanation:

We are given the following information:

After an antibiotic tablet is taken, the concentration of the antibiotic in the bloodstream is modeled by the function where the time t is measured in hours and C is measured in \mu g/mL

C(t) = 8(e^{(-0.4t)}-e^{(-0.6t)})

Thus, we are given the time interval [0,12] for t.

  • We can apply the first derivative test, to know the absolute maximum value because we have a closed interval for t.
  • The first derivative test focusing on a particular point. If the function switches or changes from increasing to decreasing at the point, then the function will achieve a highest value at that point.

First, we differentiate C(t) with respect to t, to get,

\frac{d(C(t))}{dt} = 8(-0.4e^{(-0.4t)}+ 0.6e^{(-0.6t)})

Equating the first derivative to zero, we get,

\frac{d(C(t))}{dt} = 0\\\\8(-0.4e^{(-0.4t)}+ 0.6e^{(-0.6t)}) = 0

Solving, we get,

8(-0.4e^{(-0.4t)}+ 0.6e^{(-0.6t)}) = 0\\\displaystyle\frac{e^{-0.4}}{e^{-0.6}} = \frac{0.6}{0.4}\\\\e^{0.2t} = 1.5\\\\t = \frac{ln(1.5)}{0.2}\\\\t \approx 2

At t = 0

C(0) = 8(e^{(0)}-e^{(0)}) = 0

At t = 2

C(2) = 8(e^{(-0.8)}-e^{(-1.2)}) = 1.185

At t = 12

C(12) = 8(e^{(-4.8)}-e^{(-7.2)}) = 0.059

Thus, the maximum concentration of the antibiotic during the first 12 hours is 1.185 \mu g/mL at t= 2 hours.

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3 years ago
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Answer:

3

Step-by-step explanation:


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