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Anna11 [10]
3 years ago
14

Help idc how you solve it answer it plz

Mathematics
2 answers:
dezoksy [38]3 years ago
7 0

Answer:

x = -55

Step-by-step explanation:

NISA [10]3 years ago
5 0

Answer: -55

Step-by-step explanation: ✔️

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How many cds did he buy?
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Find the equation of the line that
olganol [36]

Answer:

y=\frac{1}{2}x-2

Step-by-step explanation:

Perpendicular lines have negative reciprocal gradients(slopes) so the slope of your new line would be 1/2. Then you use the point to find the new y-intercept

y=mx+b

2=\frac{1}{2}(8)+b

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y=\frac{1}{2}x-2

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Given vectors u = (-3, 2) and v = (2, 1), what is the measure of the angle between the vectors?
BaLLatris [955]

Answer:

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Step-by-step explanation:

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3 0
3 years ago
Read 2 more answers
What is this problem -12=4(x-7)-8x
Fofino [41]

-12=4(x-7)-8x

One solution was found :

                  x = -4

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :


                    -12-(4*(x-7)-8*x)=0


Step by step solution :

Step  1  :

Equation at the end of step  1  :

 -12 -  (4 • (x - 7) -  8x)  = 0

Step  2  :

Step  3  :

Pulling out like terms :

3.1     Pull out like factors :


  4x + 16  =   4 • (x + 4)


Equation at the end of step  3  :

 4 • (x + 4)  = 0

Step  4  :

Equations which are never true :

4.1      Solve :    4   =  0

Hope this helps you, Have a nice day.

4 0
3 years ago
A cargo grain leaves Chicago at noon travelling west at 120 km/h. At 2 pm, a passenger train leaves Chicago travelling east at 3
AfilCa [17]

Answer:

a) The trains will be 1520 km apart at 2:40 pm for the cargo train and at 4:40 pm for the passenger train.

b) At that time the cargo train has traveled 560.04 km and the passenger train has traveled 960.12 km.

Step-by-step explanation:

a) First, we need to find the distance traveled by the cargo train in the two hours before the passenger train leaves Chicago:

x_{1} = v_{1}t_{1} = 120 km/h*2h = 240 km                    

Now, we can find the time when the trains will be 1520 km apart:

1520 km = (x_{1} + 240 km) + x_{2}      

Where 1 is for the cargo train and 2 is for the passenger train.

1520 km = (v_{1}*t_{1} + 240 km) + v_{2}t_{2}      

Since we need to calculate the time when the trains are 1520 km apart, t₁ = t₂, so:

1520 km = (v_{1}*t + 240 km) + v_{2}t              

t = \frac{1520 km - 240 km}{120 km/h + 360 km/h} = 2.667h

For the cargo train, it will be 1520 km apart from the passenger train at:

t_{1} = 12 pm + 2 h + 40 min = 2:40 pm

And for a passenger train, it will be 1520 km apart from the cargo train at:

t_{2} = 2 pm + 2 h + 40 min = 4:40 pm  

Hence, the trains will be 1520 km apart at 2:40 pm for the cargo train and at 4:40 pm for the passenger train.  

b) The distance traveled by both trains is given by:

x_{1} = v_{1}*t + 240 km = 120 km/h*2.667 h + 240 km = 560.04 km    

x_{2} = v_{2}*t = 360 km/h*2.667 h = 960.12 km    

Therefore, at that time the cargo train has traveled 560.04 km and the passenger train has traveled 960.12 km.

I hope it helps you!        

5 0
2 years ago
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