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Sergeeva-Olga [200]
2 years ago
15

The average yearly rainfall in Lakeview is 21.55 inches. What is the total amount of rainfall in inches in Lakeview in 5.75 year

s?
A-123.9125 inches
B-1,239.125 inches
C-12.39125 inches
D-27.3 inches
Mathematics
1 answer:
motikmotik2 years ago
7 0

Answer:

1. ANS: C

To round to the nearest integer, look at the digit in the tenths place. If it is greater than or equal to 5, round to

the next integer. If it is less than 5, keep the same integer.

53.8 + 13.8 ≈ 54 + 14 = 68

Feedback

A Perform the correct operation.

B To round to the nearest integer, look at the digit in the tenths place. If it is greater than

or equal to 5, round to the next integer. If it is less than 5, keep the same integer.

C Correct!

D Perform the correct operation.

PTS: 1 DIF: Basic REF: Page 150

OBJ: 3-1.1 Estimating Sums and Differences of Decimals NAT: 8.1.2.b

TOP: 3-1 Estimate with Decimals KEY: decimal | difference | estimate | sum

2. ANS: A

Round each number to the nearest nonzero integer or to a number that is easy to multiply.

–25.46 • 18.73 ≈ –25 • 20 = –500

Feedback

A Correct!

B Multiply, not add.

C Round each number to the nearest nonzero integer or to a number that is easy to

multiply, and then multiply.

D Check the signs.

PTS: 1 DIF: Average REF: Page 151

OBJ: 3-1.2 Estimating Products and Quotients of Decimals NAT: 8.1.2.b

TOP: 3-1 Estimate with Decimals KEY: decimal | estimate | product | quotient

3. ANS: D

Round the numbers so that they divide without leaving a remainder.

40.7 ÷ (–4.4) ≈ 40 ÷ (–5) = –8

Feedback

A Round the numbers so that they divide without leaving a remainder, and then divide.

B Check the signs.

C Perform the correct operation.

D Correct!

PTS: 1 DIF: Average REF: Page 151

OBJ: 3-1.2 Estimating Products and Quotients of Decimals NAT: 8.1.2.b

TOP: 3-1 Estimate with Decimals KEY: decimal | estimate | product | quotient

ID: A

2

4. ANS: A

An estimate can help you decide whether Maria’s calculation is reasonable.

To estimate, round each number to the nearest whole number. Then, add.

The estimate 93 + 89 + 97 + 93 + 86 = 458 is equivalent to Maria’s calculation, so 458 is a reasonable

answer.

Feedback

A Correct!

B To estimate, round each number to the nearest whole number.

PTS: 1 DIF: Average REF: Page 151 OBJ: 3-1.3 Application

NAT: 8.1.3.g TOP: 3-1 Estimate with Decimals KEY: decimal | estimate | quotient | sum

5. ANS: D

Line up the decimal points, and then add.

31.9

+ 6.9

38.8

Feedback

A Check your calculations.

B Line up the decimal points, and then add.

C Place the decimal point in the correct location.

D Correct!

PTS: 1 DIF: Basic REF: Page 154 OBJ: 3-2.1 Adding Decimals

NAT: 8.1.3.a TOP: 3-2 Adding and Subtracting Decimals

KEY: addition | decimal

6. ANS: D

Line up the decimal points, and then subtract. If necessary, use zeros as placeholders and/or regroup.

91.4

− 87.7

3.7

Feedback

A Check your calculations.

B Line up the decimal points, and then subtract.

C Perform the correct operation.

D Correct!

PTS: 1 DIF: Average REF: Page 155 OBJ: 3-2.2 Subtracting Decimals

NAT: 8.1.3.a TOP: 3-2 Adding and Subtracting Decimals

KEY: decimal | subtraction  

ID: A

3

7. ANS: D

Line up the decimal points, and then subtract. If necessary, regroup.

433.4

− 347.9

85.5

Mr. Romito drove 85.5 miles more miles on the first day than on the second day.

Feedback

A Line up the decimal points, and then subtract.

B Place the decimal point in the correct location.

C Check your calculations.

D Correct!

PTS: 1 DIF: Average REF: Page 155 OBJ: 3-2.3 Application

NAT: 8.1.3.g TOP: 3-2 Adding and Subtracting Decimals

KEY: addition | decimal | subtraction

8. ANS: B

Line up the decimal points, and then add.

14.91

+ 3.34

18.25

The corned beef and the cabbage cost $18.25.

Feedback

A Check your calculations.

B Correct!

C Line up the decimal points, and then add.

D Place the decimal point in the correct location.

PTS: 1 DIF: Average REF: Page 155 OBJ: 3-2.3 Application

NAT: 8.1.3.g TOP: 3-2 Adding and Subtracting Decimals

KEY: addition | decimal | subtraction

ID: A

4

9. ANS: A

Multiply the numbers. The product should have the same number of decimal places as the sum of the decimal

places in the factors.

Feedback

A Correct!

B Place the decimal point in the correct location.

C First, multiply the numbers. Then, place the decimal point in the correct location.

D First, multiply the numbers. Then, place the decimal point in the correct location.

PTS: 1 DIF: Basic REF: Page 160

OBJ: 3-3.1 Multiplying Integers by Decimals NAT: 8.1.3.a

TOP: 3-3 Multiplying Decimals KEY: decimal | integers | multiplication

10. ANS: A

Multiply the numbers. The product should have the same number of decimal places as the sum of the decimal

places in the factors.

Feedback

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Solve for x<br> 2800 = 400.210x
dusya [7]

Answer:

2800=400.21x

x = 6.996327

3 0
3 years ago
10.Which of the following values does not satisfy the inequality ?
kupik [55]

Answer:

The answer is -4

Step-by-step explanation:

-2x-6<=1

-2(-4)-6<=1

8-6<=1

2<=1 which is False

-2x-6<=1

-2(-3)-6<=1

6-6<=1

0<=1 which is True

-2x-6<=1

-2(-2)-6<=1

4-6<=1

-2<=1 which is True

-2x-6<=1

-2(-1)-6<=1

2-6<=1

-4<=1 which is True

7 0
2 years ago
About 33% of people who get their feet examined are found to have an ingrown toenail. What is the probability of a podiatrist ex
enot [183]

Answer:

The correct answer is 0.94147

Step-by-step explanation:

Let A denote the event that the podiatrist finds the first person with an ingrown toenail.

And (1 - A) denote the event that the podiatrist does not find the ingrown toenail.

While examining seven people, the podiatrist can find the very first person to have an ingrown toenail. Similarly he can find the second patient to have the ingrown toenail. Going in this way the probability of the first person to have an ingrown toenail is given by:

= A + (1 - A) × A + (1 - A) × (1 - A) × A + (1 - A) × (1 - A) × (1 - A) × A + (1 - A) × (1 - A) × (1 - A) × (1 - A) × A + (1 - A) × (1 - A) × (1 - A) × (1 - A) × (1 - A) × A + (1 - A) × (1 - A) ×  (1 - A) × (1 - A) × (1 - A) × (1 - A) × A.

= \frac{1}{3} + \frac{2}{3} \frac{1}{3} + \frac{2}{3} \frac{2}{3} \frac{1}{3} + \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{1}{3} + \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{1}{3} + \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{1}{3} + \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{2}{3} \frac{1}{3} .

= \frac{1}{3} + \frac{2}{3} \frac{1}{3} + (\frac{2}{3}) ^{2} \frac{1}{3} + (\frac{2}{3})^{3} \frac{1}{3} + (\frac{2}{3})^{4} \frac{1}{3} + (\frac{2}{3})^{5} \frac{1}{3} + (\frac{2}{3})^{6} \frac{1}{3}.

= 0.94147

We can also solve the above expression by using the geometric progression formula as well where common ratio is given by \dfrac{2}{3}.

8 0
3 years ago
Find an equation for the nth term of the arithmetic sequence.
Irina18 [472]

Answer:

The equation of the nth term is an = -621 + 42n

Step-by-step explanation:

* Lets revise the arithmetic sequence

- There is a constant difference between each two consecutive numbers

- Ex:

# 2  ,  5  ,  8  ,  11  ,  ……………………….

# 5  ,  10  ,  15  ,  20  ,  …………………………

# 12  ,  10  ,  8  ,  6  ,  ……………………………

* General term (nth term) of an Arithmetic sequence:

- U1 = a  ,  U2  = a + d  ,  U3  = a + 2d  ,  U4 = a + 3d  ,  U5 = a + 4d

- Un = a + (n – 1)d, where a is the first term , d is the difference

  between each two consecutive terms

, n is the position of the term

* Lets solve the problem

∵ an = a + (n - 1)d

∴ a14 = a + (14 - 1)d

∴ a14 = a + 13d

∵ a14 = -33

∴ a + 13d = -33 ⇒ (1)

- Similar we can find another equation from a15

∵ a15 = a + (15 - 1)d

∴ a15 = a + 14d

∵ a15 = 9

∴ a + 14d = 9 ⇒ (2)

- We will solve equations (1) and (2) to find a and d

* Lets subtract equation (2) from equation (1)

∴ (a - a) + (13 - 14)d = (-33 - 9)

∴ -d = -42 ⇒ × both sides by -1

∴ d = 42

- Substitute this value of d in equation (1) or (2)

∵ a + 13d = -33

∵ d = 42

∴ a + 13(42) = -33

∴ a + 546 = -33 ⇒ subtract 546 from both sides

∴ a = -579

* Now lets write the equation of the nth term

∵ an = a + (n - 1)d

∵ a = -579 and d = 42

∴ an = -579 + (n - 1) 42 ⇒ open the bracket

∴ an = -579 + 42n - 42

∴ an = -621 + 42n

* The equation of the nth term is an = -621 + 42n

6 0
2 years ago
PLS HELP ASAPPP I WILL GIVE BRAINLIEST
FrozenT [24]

Answer:

Yes, it is.

Step-by-step explanation:

6 0
2 years ago
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