(a) Take the Laplace transform of both sides:


where the transform of
comes from
![L[ty'(t)]=-(L[y'(t)])'=-(sY(s)-y(0))'=-Y(s)-sY'(s)](https://tex.z-dn.net/?f=L%5Bty%27%28t%29%5D%3D-%28L%5By%27%28t%29%5D%29%27%3D-%28sY%28s%29-y%280%29%29%27%3D-Y%28s%29-sY%27%28s%29)
This yields the linear ODE,

Divides both sides by
:

Find the integrating factor:

Multiply both sides of the ODE by
:

The left side condenses into the derivative of a product:

Integrate both sides and solve for
:


(b) Taking the inverse transform of both sides gives
![y(t)=\dfrac{7t^2}2+C\,L^{-1}\left[\dfrac{e^{s^2}}{s^3}\right]](https://tex.z-dn.net/?f=y%28t%29%3D%5Cdfrac%7B7t%5E2%7D2%2BC%5C%2CL%5E%7B-1%7D%5Cleft%5B%5Cdfrac%7Be%5E%7Bs%5E2%7D%7D%7Bs%5E3%7D%5Cright%5D)
I don't know whether the remaining inverse transform can be resolved, but using the principle of superposition, we know that
is one solution to the original ODE.

Substitute these into the ODE to see everything checks out:

Pls. see attachment.
The perimeter of the triangle is 146.
Answer:
x
=
4
or
x
=
−
4
Explanation:
First divide throughout by
2
to get
x
2
=
16
Now take the square root on both sides to get
x
=
±
4
.
You may now substitute the values of
x
=
4
and
x
=
−
4
back into the original equation and check that it satisfies the equation which it does.
Step-by-step explanation:
Answer:
The answer is
n=5 3/5
Step-by-step explanation:
first collect the like terms:
2-1/2n=3n+16
then...
3n-1/2=16-2
==2 1/2n = 14
===n=5 3/5
1) you can buy 6 candy bars because $5.10 / $0.85 =
6.
To check: 6*0.85=5.10
2) you can find the answer by adding 3 to 12. 3+12=15 n=15 and it said n can be greater than or equal so
N(greater than or equal to sign) 15.
To check: 15-3=12
12=12
16-3>12
13>12
7) x-7=12
+7 +7
X=19
To check: 19-7=12
12=12
8) y/8=7
*8 *8
Y= 56
To check: 56/8=7
7=7
9) 10-4x=6x
+4x +4x
10=10x
/10 /10
X=1
To check: 10-4(1)=6(1)
10-4=6
6=6
Hope this helped!