<span>There are 4 long rows and 5 short rows in the theater. x represents the number of chairs in each long row and y represents the number of chairs in each short row.
So, total number of chairs in 4 long rows= 4x
Total number of chairs in 5 short rows = 5y
Total number of chairs in the theater on a normal day = 4x + 5y
When 2 chairs are added to each long row, the number of chairs will change to (x+2).
So, total number of chairs in 4 long rows will be = 4(x+2)
When 3 chairs are added to each short row, the number of chairs will change to (y+3)
So, total number of chairs in 5 short rows will be = 5(y+3)
Thus, total number of chairs in the theater in rush day = 4(x+2) + 5(y+3)
= 4x + 8 + 5y + 15
= 4x + 5y + 23
Thus we can say the number of chairs increase by 23 as compared to a normal day.
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Y intercept = when x = 0
Plug in x = 0
0 + 3y = 6
3y = 6, y = 2
Solution: a, (0,2)
Answer: X does not intercept (none)
Y=(0,5)
Step-by-step explanation:
1: -5 = 3m + c
2: -2 = 0 + c
From equation 2, we knew c = -2
So we sub into equation 1 and got the value of m
-5 = 3m - 2
m = -1
The equation of line is y = -x - 2
