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3 years ago

5

The cost of 2 television and 3 DVD player is $1,421 . The cost of 1 DVD player is half the cost of 1 television . What is the co

st of 1 television ?

1 answer:

alexgriva [62]3 years ago

4 0

T=cost of one television D= cost of one DVD player 2t+3d= 1421 D=t(1/2) Replace d by t(1/2) 2t+3(t1/2)= 1421 3.5 t = 1421 T= 691.7 $ Good luck

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A hiker is walking down a mountain. She walked 5,978 feet in 17 minutes. In that time, she descended 1,024 feet from the top

Karo-lina-s [1.5K]

First walk=descend of 1024 feet in 17 minutes
second walk=descend of 500 feet in 7 minutes

so in total she descended 1024+500=1524 feet in 7+17=24 minutes
as an average rate this equals 1524/24=63.5 feet/minute descended
or an average rate of -63.5 feet/minute in altitude (note the minus)

5 0

3 years ago

Mrs. Lee randomly surveyed 25 of her 125 students about their pets. Her survey

raketka [301]

Answer:

My figure would have 3 overlapping regions, each representing dogs, cats, or fish. The overlapping parts represent those areas where owners have more than one pet.

Now, we know the number owners that have dogs is 14 (place this number outside one of the 3 large regions and call it dogs. Do the same for cats (10) and fish (5). At this point it's important to remember that only some of the 14 dog owners have only dogs. Same for cats and fish.

In fact, we know that 4 owners have both dogs and cats. So, on the figure where the dog region and cat region overlap, write 4. Do the same where the dog and fish regions overlap and write 3.

What this means is that of the 14 dog owners, 7 of them own more than a dog. So, 7 dog owners own only dogs:

14 - 7 = 7

Use the same approach for each of the other pets:

Cats: 10 owners have cats; 4 have dogs and cats and 1 has a cat and a fish. So, 5 owners have only cats (10 - 5).

Fish: 5 owners have fish; 3 have dogs and fish and 1 has a cat and a fish. So 1 owner has only fish (5 - 4).

Then, in summary:

Owners that have:

Only Dogs - 7

Only Cats - 5

Only Fish - 1

Dogs AND Cats - 4

Dogs AND Fish - 3

Cats AND Fish - 1

The total number of owners that have at least one pet then is:

7 + 5 + 1 + 4 + 3 + 1 = 21

So, since there are 26 total owners, 5 must not own a dog, cat, or fish.

hope it helps!!!!!!!!!!!!!!!!!!!

I put lot's of work into it

4 0

2 years ago

In one day, The Tool Shed rented out 25 self-propelled and riding mowers for a total fee of $900. The dolly rental cost was $20

masha68 [24]

They rented out 5 self-propelled mowers and 20 riding mowers.

Data;

Total number of tool rented out = 25
Cost of tools rented = $900

<h3>System of Equations</h3>

To solve this problem, we have to write a system of equations to represent the problem.

since we have

x = self - propelled mower
y = riding mowers

Let's write equations with these variables.

$x+y = 25...equation (i)\\20x+40y = 900...equation(ii)$

From equation (i)

$x+y= 25\\x = 25 - y...equation(iii)$

Put equation (iii) into equation (ii)

$20x+40y=900\\x = 25-y\\20(25-y)+40y=900\\\\500-20y+40y=900\\500+20y=900\\20y=900-500\\20y=400\\\frac{20y}{20}=\frac{400}{20}\\ y=20$

Let's substitute the value of y into equation(i)

$x+y =25\\x+20 = 25\\x = 25 - 20\\x = 5$

From the calculations above, they rented 5 self-propelled mowers and 20 riding mowers.

Learn more on system of equations here;

brainly.com/question/13729904

4 0

2 years ago

Solve for m and b <br><br>(5,14) and (3,10)

Elis [28]

Y=mx+b

Y1-Y2/X1-X2

14-10/5-3 = 4/2 = 2

Plug in (3,10):
(10)=2(3)+b

Solve:
10=6+b

B=4
M=2

6 0

3 years ago

Compute the following.<br> f(40) − f(0)/40 − 0

Rudik [331]

Answer:

the slope of the tangent line at (40, f(40))the slope of the tangent line at (15, f(15)) the slope of the tangent line at (10, f(10))the slope of the line segment from (10, f(10)) to (40, f(40))

6 0

2 years ago