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Natasha2012 [34]
3 years ago
13

Can someone please help me with this question

Mathematics
1 answer:
zmey [24]3 years ago
5 0

Answer:

D

Step-by-step explanation:not very sure but took the test and think I got it right

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The CEO of the Jen and Benny's ice cream company is concerned about the net weight of ice cream in their 50 ounce ice cream tubs
MissTica

Answer:

t=\frac{54.98-52}{\frac{8.43}{\sqrt{26}}}=1.8025  

We need to find the degrees of freedom given by:

df = n-1= 26-1 = 25

Since is a right tailed test the p value would be:  

p_v =P(t_{25}>1.8025)=0.0418  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the average is higher than 52 at 5% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=54.98 represent the sample mean

s=8.43 represent the sample deviation

n=26 sample size  

\mu_o =52 represent the value that we want to test  

\alpha=0.05 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is higher than 52, the system of hypothesis would be:  

Null hypothesis:\mu \leq 52  

Alternative hypothesis:\mu > 52  

Since we don't know the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

t=\frac{54.98-52}{\frac{8.43}{\sqrt{26}}}=1.8025  

P-value  

We need to find the degrees of freedom given by:

df = n-1= 26-1 = 25

Since is a right tailed test the p value would be:  

p_v =P(t_{25}>1.8025)=0.0418  

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the average is higher than 52 at 5% of signficance.  

7 0
3 years ago
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If one side of a triangle is 5cm what is the maximum difference of other two side​
gtnhenbr [62]

Answer:

100cm

Step-by-step explanation:

the difference between of 5cm

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What is the answer to this problem
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Answer: P = $47,120.53
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If 18% of the beads in a bag are green, 25% are red, and 40% are purple, what is the probability of choosing a green bead and th
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the answer is a)22 %

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I need help finding the X in these equations
krek1111 [17]

Answer:

For D I believe it would be 6

Step-by-step explanation:

I believe 6 because is you do 108÷18 you get 6 and then it would be 6/108 = 7/18 which is true.

Might not be correct and I don't know the others sorry!

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