30%,
1-5=20%
so 50%-20%= 30%
well, the difference from 5600 to 4200 is 1400.
If we take 5600 to be the 100%, how much is 1400 off of it in percentage?
![\begin{array}{ccll} amount&\%\\ \cline{1-2} 5600&100\\ 1400&x \end{array}\implies \cfrac{5600}{1400}=\cfrac{100}{x}\implies 4=\cfrac{100}{x} \\\\\\ 4x=100\implies x=\cfrac{100}{4}\implies x=25](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bccll%7D%20amount%26%5C%25%5C%5C%20%5Ccline%7B1-2%7D%205600%26100%5C%5C%201400%26x%20%5Cend%7Barray%7D%5Cimplies%20%5Ccfrac%7B5600%7D%7B1400%7D%3D%5Ccfrac%7B100%7D%7Bx%7D%5Cimplies%204%3D%5Ccfrac%7B100%7D%7Bx%7D%20%5C%5C%5C%5C%5C%5C%204x%3D100%5Cimplies%20x%3D%5Ccfrac%7B100%7D%7B4%7D%5Cimplies%20x%3D25)
Answer:
28 hours
Step-by-step explanation:
6x28=168
Answer:
17.3
Step-by-step explanation:
To solve this equation, you need to use the pythagorean theorem which is:
![a^{2} +b^{2}= c^{2}](https://tex.z-dn.net/?f=a%5E%7B2%7D%20%2Bb%5E%7B2%7D%3D%20c%5E%7B2%7D)
a= length
b= height
c= hypotenuse
First, substitute in your values for the equation:
![10^2+b^{2} =20^{2}](https://tex.z-dn.net/?f=10%5E2%2Bb%5E%7B2%7D%20%3D20%5E%7B2%7D)
Then, use the squares in the equation:
![100+b^{2} =400](https://tex.z-dn.net/?f=100%2Bb%5E%7B2%7D%20%3D400)
Then, subtract 100 from both sides to isolate b:
![b^{2} =300](https://tex.z-dn.net/?f=b%5E%7B2%7D%20%3D300)
Finally, square root both sides to get your answer:
![b=17.3205080757](https://tex.z-dn.net/?f=b%3D17.3205080757)
Then round to the nearest tenth which gives you 17.3.