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vredina [299]
3 years ago
9

In the New York State Numbers Lottery, you pay $1 and can bet that the sum of the numbers that come up is 13. The probability of

winning is 0.075, and if you win, you win $6.50, which is a profit of $5.50. If you lose, you lose $1. What is the expected value of your profit? Is it an expected gain or an expected loss?
Mathematics
1 answer:
Harman [31]3 years ago
7 0

Answer:

The expected value of profit is -0.5125. This is expected loss as value is negative.        

Step-by-step explanation:

We are given the following in the question:

P(winning) = 0.075

Thus,

P(Loosing) =

1 - 0.075 = 0.925

If we win we gain a profit of $5.50 and if we loose the lottery, we loose $1.

Thus, we can form the probability distribution in the following manner:

  Event:      Winning       Loosing

Profit(x):      +5.50               -1

     P(x):       0.075             0.925

We have to calculate the expected value of the profit.

E(X) = \displaystyle\sum x_i(P(x_i))\\E(x) = +5.50(0.075) + (-1)(0.925)\\E(x) = -0.5125

Thus, the expected value of profit is -0.5125. This is expected loss as value is negative.

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Question
balandron [24]

Answer:

The approximate percentage of SAT scores that are less than 865 is 16%.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

Approximately 68% of the measures are within 1 standard deviation of the mean.

Approximately 95% of the measures are within 2 standard deviations of the mean.

Approximately 99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean of 1060, standard deviation of 195.

Empirical Rule to estimate the approximate percentage of SAT scores that are less than 865.

865 = 1060 - 195

So 865 is one standard deviation below the mean.

Approximately 68% of the measures are within 1 standard deviation of the mean, so approximately 100 - 68 = 32% are more than 1 standard deviation from the mean. The normal distribution is symmetric, which means that approximately 32/2 = 16% are more than 1 standard deviation below the mean and approximately 16% are more than 1 standard deviation above the mean. So

The approximate percentage of SAT scores that are less than 865 is 16%.

8 0
3 years ago
in the figure given alongside, AB is the diameter of circle with centre O. If <COD=50°, find the size of <CED. ​
Ksju [112]

Answer:

50

Step-by-step explanation:

code in parm so the angle o is equal to e

that is a property of the parm

5 0
2 years ago
In which quadrant is ( 5,4 ) is located<br>this is hw and i wanna get a good grade plz helpp!!!!
Andre45 [30]
(5,4)

On a system of 2 perpendicular axis with O as origine, the pair (5,4) means:

5 is the distance from the origin O and situated on x-axis (on the right of O)
4 is the distance from the origin O and situated on y-axis (above O)

Then the pair (5,4) is situated in the 1st Quadrant

8 0
3 years ago
Change the units up above to the correct answer from (a) to (d)
Leto [7]

Answer:

Step-by-step explanation:

1 cm = 10 mm

a) 0.1 cm = 1 mm

1 mm = 1000 m

b) 25000mm = 25 m

1 g = 0.001 kg

c) 7g = 0.007 kg

1ml = 0.000001

d) 30000ml = 0.03 kl

6 0
3 years ago
The amount of protein that an individual must consume is different for every person. There are solid theoretical ideas that sugg
amid [387]

Answer:

The proportion of the population that have a protein requirement less than 0.60 g P • kg-1 • d-1 is 0.239, that is, 239 persons for every 1000, or simply 23.9% of them.

\\ 0.239 =\frac{239}{1000}\;or\;23.9\%

Step-by-step explanation:

From the question, we have the following information:

  • The distribution for protein requirement is <em>normally distributed</em>.
  • The population mean for protein requirement for adults is \\ \mu= 0.65 gP*kg^{-1}*d^{-1}
  • The population standard deviation is \\ \sigma =0.07 gP*kg^{-1}*d^{-1}

We have here that protein requirements in adults is normally distributed with defined parameters. The question is about <em>the proportion</em> <em>of the population</em> that has a requirement less than \\ x = 0.60 gP*kg^{-1}*d^{-1}.

For answering this, we need to calculate a <em>z-score</em> to obtain the probability of the value <em>x </em>in this distribution using a <em>standard normal table</em> available on the Internet or on any statistics book.

<h3>z-score</h3>

A z-score is expressed as

\\ z = \frac{x - \mu}{\sigma}

For the given parameters, we have:

\\ z = \frac{0.60 - 0.65}{0.07}

\\ z = \frac{0.60 - 0.65}{0.07}

\\ z = -0.7142857

<h3>Determining the probability</h3>

With this value for <em>z</em> at hand, we need to consult a standard normal table to determine what the probability of this value is.

The value for z = -0.7142857 is telling us that the requirement for protein is below the population mean (negative sign indicates this). However, most standard normal tables give a probability that a statistic is less than z and for values greater than the mean (in other words, positive values). To overcome this, we need to take the complement of the probability given for z-score z = 0.7142857, that is, subtract from 1 this probability, which is possible because the normal distribution is <em>symmetrical</em>.

Tables have values for <em>z</em> with two decimal places, then, for z = 0.7142857, we need to rewrite it as z = 0.71. For this value, the <em>standard normal table</em> gives a value of P(z<0.71) = 0.76115.

Therefore, the cumulative probability for values less than x = 0.60 which corresponds to a z-score = -0.7142857 is approximately:

\\ P(x

\\ P(x (rounding to three decimal places)

That is, the proportion of the population that have a protein requirement less than 0.60 g P • kg-1 • d-1 is

\\ 0.239 =\frac{239}{1000}\;or\;23.9\%

See the graph below. The shaded area is the region that represents the proportion asked in the question.

5 0
4 years ago
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