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ivann1987 [24]
3 years ago
12

What is the rate of change for the line that goes through the points (8,14) and (11, 19.25)​

Mathematics
1 answer:
elixir [45]3 years ago
4 0

Answer:

<h3>1.75</h3>

Step-by-step explanation:

The rate of change for the line that goes through the points (8,14) and (11, 19.25)​ is known as the slope expressed as;

slope m = y2-y1/x2-x1

Substitute the coordinate pairs into the formula;

m = 19.25-14/11-8

m = 5.25/3

m = 1.75

Hence the rate of change for the line is 1.75.

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Which increase faster, f(x)=5x or g(x)=5^x
hichkok12 [17]

g(x) = 5^x is your answer

Plug in increasing numbers for x to get the output.

For example: when x = 1

f(1) = 5(1) = 5

g(1) = 5^(1) = 5

when x = 2

f(2)= 5(2) = 10

g(2) = 5^(2) = 25

when x = 3

f(3) = 5(3) = 15

g(3) = 5^(3) = 125

~

From the example above, we see that g(x) = 5^x is your answer

~

5 0
3 years ago
The fuel for a chain saw is a mix of oil and gasoline. The ratio of ounces of oil to gallons of gasoline is 9:19. There are 152
LUCKY_DIMON [66]
9/19 = x / 152....9 oz oil to 19 gallons gas = x oz oil to 152 gallons gas
cross multiply because this is a proportion
(19)(x) = (152)(9)
19x = 1368
x = 1368/19
x = 72 oz of oil <==
5 0
3 years ago
Read 2 more answers
What is the equation of the line?
spin [16.1K]

Answer:

y=1/2x+2

Step-by-step explanation:

You want to find the equation for a line that passes through the two points:

(0,2) and (-4,0).

First of all, remember what the equation of a line is:

y = mx+b

Where:

m is the slope, and

b is the y-intercept

First, let's find what m is, the slope of the line...

The slope of a line is a measure of how fast the line "goes up" or "goes down". A large slope means the line goes up or down really fast (a very steep line). Small slopes means the line isn't very steep. A slope of zero means the line has no steepness at all; it is perfectly horizontal.

For lines like these, the slope is always defined as "the change in y over the change in x" or, in equation form:

So what we need now are the two points you gave that the line passes through. Let's call the first point you gave, (0,2), point #1, so the x and y numbers given will be called x1 and y1. Or, x1=0 and y1=2.

Also, let's call the second point you gave, (-4,0), point #2, so the x and y numbers here will be called x2 and y2. Or, x2=-4 and y2=0.

Now, just plug the numbers into the formula for m above, like this:

m= 0 - 2-4 - 0 or... m= -2-4 or... m=1/2

So, we have the first piece to finding the equation of this line, and we can fill it into y=mx+b like this:

y=1/2x+b

Now, what about b, the y-intercept?

To find b, think about what your (x,y) points mean:

(0,2). When x of the line is 0, y of the line must be 2.

(-4,0). When x of the line is -4, y of the line must be 0.

Because you said the line passes through each one of these two points, right?

Now, look at our line's equation so far: y=1/2x+b. b is what we want, the 1/2 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the two points (0,2) and (-4,0).

So, why not plug in for x and y from one of our (x,y) points that we know the line passes through? This will allow us to solve for b for the particular line that passes through the two points you gave!.

You can use either (x,y) point you want..the answer will be the same:

(0,2). y=mx+b or 2=1/2 × 0+b, or solving for b: b=2-(1/2)(0). b=2.

(-4,0). y=mx+b or 0=1/2 × -4+b, or solving for b: b=0-(1/2)(-4). b=2.

See! In both cases we got the same value for b. And this completes our problem.

The equation of the line that passes through the points

(0,2) and (-4,0)

is

y=1/2x+2

4 0
3 years ago
Two airplanes leave the airport. Plane A departs at a 44° angle from the runway, and plane B departs at a 40° angle from the run
lawyer [7]

Answer: Answer:

Plane B was farthest away from the airport

Step-by-step explanation:

"This question requires you to visualize the run way as the horizontal distance to be covered, the height from the ground as the height gained by the plane after take of and the distance from the airport as the displacement due to the angle of take off.

In plane A

The take-off angle is 44° and the height gained is 22 ft.

Apply the relationship for sine of an angle;

Sine Ф°= opposite side length÷hypotenuse side length

The opposite side length is the height gained by plane which is 22 ft

The angle is 44° and the distance the plane will be away from the airport after take-off will be represented by the value of hypotenuse

Applying the formula

sin Ф=O/H where O=length of the side opposite to angle 44° and H is the hypotenuse

In plane B

Angle of take-off =40°, height of plane=22miles finding the hypotenuse

Solution

After take-off and reaching a height of 22 ft from the ground, plane A will be 31.67 miles from the airport

After take-off and reaching a height of 22 ft from the ground, plane B will be 34.23 miles away from the airport."

Excerpt from Brainly

3 0
2 years ago
Read 2 more answers
21000.7895÷444477777
Radda [10]
<span>21000.7895÷444477777</span>= 0.00004724823

4 0
3 years ago
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