Using a system of equation, we have that:
a)
- x, which is the cost of on-site service.
- y, which is the cost of at-store service.
- z, which is the cost of by-mail service.
b)
The system is:



c)
The cost of one on-site repair service is of $90.
Item a:
The variables are:
- x, which is the cost of on-site service.
- y, which is the cost of at-store service.
- z, which is the cost of by-mail service.
Item b:
On-site service costs <u>3 times as much as at-store service</u>, thus:

By mail service costs <u>$10 less than at-store</u> service, thus:

Last week, the shop completed <u>15 services on-site, 40 services at-store, and 5 services by mail for total sales of $3100</u>, thus:

The system is:



Item c:
- The cost of one on-site repair service is x.
- First, replacing the first two equations into the third, we find y, and then with it we find x.






Then

The cost of one on-site repair service is of $90.
A similar problem is given at brainly.com/question/24823220
Answer:
A
Step-by-step explanation:
Luis because the sample is taken from the population of all seventh graders.
the answers are <span>the lower quartile and the maximum and The minimum and the upper quartile.</span>
Step-by-step explanation:
so, if I understand this correctly, the original square had a side length of 8 m.
now we transform this square into one with side length 1/4×8 = 8/4 = 2 m.
and the questions are what are the perimeter and the area of that new (smaller) square ?
the perimeter of a square is
4× side length = 4×2 = 8 m
the area of a square is
side length ² = 2² = 4 m²