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raketka [301]
3 years ago
10

Help me with this please with 40 points!!!

Mathematics
2 answers:
Viktor [21]3 years ago
8 0

Answer:

4

Step-by-step explanation:

tangare [24]3 years ago
6 0
444444444444444444444444
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The probability of drawing a red marble from a bag is 34%. What is the probability of drawing a marble that is not red from the
tatuchka [14]
<span>the probability of drawing a marble that is not red from the bag is 66%</span>
5 0
3 years ago
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Find the distance between P(2, 5 ) and Q( 7 , 3)
Sloan [31]

Answer:

PQ = √(7-2)²+(3-5)²

= √ 5²+(-2)²

= √ 25+4

=√29 units

Hope it helps !

Don't forget to mark me as brainliests.

5 0
2 years ago
Perimeter, Area And Volume
san4es73 [151]

Answer:

A ≈ 1900.7 m²

Step-by-step explanation:

The area (A) of the race track is

area of outer circle - area of inner circle

= πR² - πr²

= π × 63² - π × 58²

= π (63² - 58² )

= π(3969 - 3364)

= π × 605

≈ 1900.7 m² ( to 1 dec. place )

6 0
3 years ago
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Which expression is equivalent to 3^2 x 3^6<br><br> 3^12 <br><br> 9^12<br><br> 9^8<br><br> 3^8
Evgen [1.6K]

Answer:

{3}^{8}

Step-by-step explanation:

1) Use product rule: x^a x^b = x^a+b.

{3}^{8}

2) Simplify.

6561

The answer is option D) 3⁸.

5 0
3 years ago
Consider sampling heights from the population of all female college soccer players in the United States. Assume the mean height
Verizon [17]

Answer:

The approximated value of the standard deviation is 0.35.

Step-by-step explanation:

According to the Central Limit Theorem if we have an unknown population with mean <em>μ</em> and standard deviation <em>σ</em> and appropriately huge random samples (<em>n</em> > 30) are selected from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.  

Then, the mean of the distribution of sample means is given by,

\mu_{\bar x}=\mu

And the standard deviation of the distribution of sample means is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

The information provided is:

<em>n</em> = 100

<em>σ</em> = 3.5

<em>μ</em> = 66

As the sample size is quite large, i.e. <em>n</em> = 100 > 30, the central limit theorem can be applied to approximate the sampling distribution of sample mean by the Normal distribution.

Then the approximated value of the standard deviation of sampling distribution of sample mean is:

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

    =\frac{3.5}{\sqrt{100}}\\\\=0.35

Thus, the approximated value of the standard deviation is 0.35.

5 0
4 years ago
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