Someone help with this pls and answer all of them!!

kompoz [17]

Answer:

The correct statements are:

A) This polynomial has a degree of 2, so the equation $x^{2} + 4x + 4$ has exactly two roots.

B: The quadratic equation $x^{2} + 4x + 4$ has one real solution, x=−2, and therefore has one real root with a multiplicity of 2.

Step-by-step explanation:

Here, the given polynomial is $f(x) = x^{2} + 4x + 4$

FUNDAMENTAL THEOREM OF ALGEBRA:

If P(x) is a polynomial of degree n ≥ 1, then P(x) = 0 has exactly n roots, including multiple and complex roots.

Now, here the given polynomial is a quadratic polynomial with degree 2.

So, by the fundamental theorem, f(x) has EXACTLY 2 roots including multiple and complex roots.

Now, solving the equation , we get that the only possible roots of the polynomial p(x) is x = -2 and x = -2

So, f(x) has only one distinct root x = -2 with a multiplicity 2.

Hence, the correct statements are:

A) This polynomial has a degree of 2, so the equation $x^{2} + 4x + 4$ has exactly two roots.

B: The quadratic equation $x^{2} + 4x + 4$ has one real solution, x=−2, and therefore has one real root with a multiplicity of 2.

4 0

4 years ago

Which point is exterior to APD

Rainbow [258]

Point E is exterior to APD

5 0

3 years ago

Read 2 more answers

Please help, thanks I’m advance!

netineya [11]

Answer:

A

Step-by-step explanation:

(x+2)©= x©+4x+4

Hsbsbjsjisoajja

3 0

3 years ago

If c is the curve given by \mathbf{r} \left( t \right = \left( 1 5 \sin t \right \mathbf{i} \left( 1 3 \sin^{2} t \right \mathbf

jonny [76]

With the curve $C$ parameterized by

$C:\mathbf r(t)=\underbrace{15\sin t}_{x(t)}\,\mathbf i+\underbrace{13\sin^2t}_{y(t)}\,\mathbf j+\underbrace{12\sin^3t}_{z(t)}\,\mathbf k$

with $0\le t\le\dfrac\pi2$ , and given the vector field

$\mathbf f(x,y,z)=x\,\mathbf i+y\,\mathbf j+z\,\mathbf k$

the work done by $\mathbf f$ on a particle moving on along $C$ is given by the line integral

$\displaystyle\int_C\mathbf f\cdot\mathrm d\mathbf r=\int\limits_{t=0}^{t=\pi/2}\mathbf f(x(t),y(t),z(t))\cdot\frac{\mathrm d\mathbf r(t)}{\mathrm dt}\,\mathrm dt$

where

$\mathrm d\mathbf r=(15\cos t\,\mathbf i+26\sin t\cos t\,\mathbf j+36\sin^2t\cos t\,\mathbf k)\,\mathrm dt$

The integral is then

$\displaystyle\int_0^{\pi/2}(15\sin t\,\mathbf i+13\sin^2t\,\mathbf j+12\sin^3t\,\mathbf k)\cdot(15\cos t\,\mathbf i+13\sin2t\,\mathbf j+18\sin t\sin2t\,\mathbf k)\,\mathrm dt$
$=\displaystyle\int_0^{\pi/2}(432\sin^5t\cos t+338\sin^3t\cos t+225\sin t\cos t$
$=269$

6 0

4 years ago

En la preparación de un perfume se cuenta con dos tipos de esencia base: 1600 ml de una y 1680 ml de otra. Se quiere envasarlas,

Lostsunrise [7]

Answer:

33,600 frascos

Step-by-step explanation:

Resolvemos esta pregunta utilizando el método mínimo común múltiple

Encuentre y enumere los múltiplos de 1600 y 1680 hasta encontrar el primer múltiplo común. Este es el mínimo común múltiplo.

Múltiplos de 1600:

1600, 3200, 4800, 6400, 8000, 9600, 11200, 12800, 14400, 16000, 17600, 19200, 20800, 22400, 24000, 25600, 27200, 28800, 30400, 32000, 33600, 35200, 36800

Múltiplos de 1680:

1680, 3360, 5040, 6720, 8400, 10080, 11760, 13440, 15120, 16800, 18480, 20160, 21840, 23520, 25200, 26880, 28560, 30240, 31920, 33600, 35280, 36960

Por lo tanto,

LCM (1600, 1680) = 33,600

La menor cantidad de frascos necesarios es 33,600 frascos.

4 0

3 years ago