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pickupchik [31]
3 years ago
13

Someone help with this pls and answer all of them!!

Mathematics
1 answer:
ad-work [718]3 years ago
3 0
6 is -2 +12
7 is -3 + 1
10 is -0.25y + 4
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Suppose both factors in a multiplication problem are multiples of 10. Why might the number of zeroes in the product be different
Lelu [443]

Answer:

Multiplying factors whose products are multiples of 10 add to the number of zeros when factors are multiplied as multiples of 10s.

Step-by-step explanation:

Let the first five multiples of ten be

10*1= 10

10*2= 20

10*3=30

10*4=40

10*5= 50

Suppose we chose 20 and 50.

Now multiplying 20 with 50 we get

20*50= 1000

IF we count the total number of zeros in the factors ( 20 and 50) they are 2.

But the number of zeros in the product (1000) are 3.

This is because when we multiply 2 with 5 we get 10 which adds to the existing number of zeros ( i.e 2) and we get a total of 3 zeros.

And multiplying 10 with 50 we get

10*50= 500

IF we count the total number of zeros in the factors ( 10 and 50) they are 2.

But the number of zeros in the product (500) are also 2.

This is because when we multiply 1 with 5 we get 5 which does not add to the existing number of zeros ( i.e 2) and the total number of zeros remain the same.

Similarly multiplying 20 with 30 we get

20*30= 600

IF we count the total number of zeros in the factors ( 20 and 30) they are 2.

But the number of zeros in the product (600) are also 2.

This is because when we multiply 2 with 3 we get 6 which does not have a zero and the total  number of zeros remain the same as in the factors.

So we see that multiplying factors whose products are multiples of 10 add to the number of zeros when factors are multiplied as multiples of 10s.

5 0
3 years ago
Seventy cards are numbered 1 through 70 , one number per card. One card is randomly selected from the deck. What is the probabil
Vanyuwa [196]

Answer:

Probability = \frac{2}{35}

Step-by-step explanation:

Given

Total = 70

First, we need to list the multiples of 5

M_5 = \{5,10,15,20,25,30,35,40,45,50,55,60,65,70\}

Then, multiples of 3M_3 = \{3,6,9,12,15,18,21,24,27,30,33,36,39,42,45,48,51,54,57,60,63,66,69\}

Next, is to list out the common elements in both

M_3\ n\ M_5 = \{15,30,45,60\}

n(M_3\ n\ M_5) = 4

The required probability is then calculated as thus:

Probability = \frac{n(M_3\ n\ M_5)}{Total}

Probability = \frac{4}{70}

Probability = \frac{2}{35}

7 0
3 years ago
A group of 30 students were asked about their favorite way to eat eggs.
alukav5142 [94]

It's too short. Write at least 20 characters to explain it well.

Your answer can't be empty

4 0
3 years ago
If F(x) = 3x - 2 and G(x) = x2 + 8, what is G(F(x))?
Nikitich [7]
<span>9x^2 - 12x + 12
Hope it helps! (:</span>
6 0
3 years ago
Read 2 more answers
Solve (−7) ⋅ (−4).<br><br> a −28<br> b −11<br> c 28<br> d 11
german
-11 because first you add -4 and -7 because when you subtract negatives you add I hope I helped and have a good day
5 0
3 years ago
Read 2 more answers
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