NEED HELP ASAP !!!!!!!!!!!!

Mathematics

1 answer:

andrew-mc [135]2 years ago

5 0

Answer:

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You might be interested in

What is the sum of all positive integers less than 300 which are divisible by 3

drek231 [11]

Answer:

14,850

Step-by-step explanation:

You need the sum of

3 + 6 + 9 + 12 + ... + 294 + 297

Factor out a 3 from the sum

3 + 6 + 9 + 12 + ... + 294 + 297 = 3(1 + 2 + 3 + 4 + ... + 98 + 99)

You need to add all integers from 1 to 99 and multiply by 3.

The sum of all consecutive integers from 1 to n is:

[n(n + 1)]/2

The sum of all consecutive integers from 1 to 99 is

[99(99 + 1)]/2

The sum you need is 3 * [99(99 + 1)]/2

3 + 6 + 9 + 12 + ... + 294 + 297 =

= 3 * [99(99 + 1)]/2

= 3 * [99(100)]/2

= 3 * 9900/2

= 14,850

4 0

2 years ago

Make up this problem yourself 3 divided by 1/2

Helen [10]

Answer:

3 : (1/2) = $\frac{6}{1} =6$

Step-by-step explanation:

Divide: 3 : $\frac{1}{2} =\frac{3}{1} *\frac{2}{1} =\frac{3 * 2}{1*1} =\frac{6}{1} =6$

Dividing two fractions is the same as multiplying the first fraction by the reciprocal value of the second fraction. The first sub-step is to find the reciprocal (reverse the numerator and denominator, reciprocal of $\frac{1}{2}$ is $\frac{2}{1}$ ) of the second fraction. Next, multiply the two numerators. Then, multiply the two denominators.