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Brilliant_brown [7]
3 years ago
6

What is the degree of the polynomial?​

Mathematics
2 answers:
sp2606 [1]3 years ago
5 0

Answer:

D. 2

Step-by-step explanation:

The degree is the biggest exponent. In this case, it is 2.

jek_recluse [69]3 years ago
3 0

Answer:

2

Step-by-step explanation:

The highest exponent is 2

therefor this is a 2nd degree polynomial

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Whats the area of the real Bedroom?
Gemiola [76]

Answer:

The answer is 18 cm.

Step-by-step explanation:

Just multiply 6 by 3.

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3 years ago
Consider the following function. f(x) = 9 − x2/3 Find f(−27) and f(27). f(−27) = f(27) = Find all values c in (−27, 27) such tha
oksano4ka [1.4K]

I guess the function is f(x)=9-x^{2/3}. Then f(-27)=0 and f(27)=0.

The derivative is f'(x)=-\dfrac23 x^{-1/3}, but there is no c such that

-\dfrac23c^{-1/3}=0

This doesn't contradict Rolle's theorem because f'(0) does not exists. In other words, f is not differentiable on (-27, 27), so the conditions of Rolle's theorem are not met. (Looks like that would be the last option, or the second to last option if the last one is "Nothing can be concluded")

6 0
3 years ago
The base diameter and the height of a cone are both equal
vampirchik [111]

Answer:

1/3 times x squared divided by 4 times pi times x.

Step-by-step explanation:

Hope this helps!

6 0
3 years ago
The zoo feeds the tortoise, rhinoceros, and zebra a total of 23 pounds of vegetables a day. How many pounds does the zoo feed th
vekshin1

If I understand your question correctly, you want to know how many pounds of vegetables the zoo feeds the animals a month if its a 30 day month?

In that case it would be 23 pounds times 30 days which is 690 pounds of vegetables. SO the zoo feeds the animals 690 pounds of vegetables to the animals each month.

Is that what your asking for?

8 0
3 years ago
The diameter of a particle of contamination (in micrometers) is modeled with the probability density function f(x)= 2/x^3 for x
natulia [17]

Answer:

a) 0.96

b) 0.016

c) 0.018

d) 0.982

e) x = 2

Step-by-step explanation:

We are given with the Probability density function f(x)= 2/x^3 where x > 1.

<em>Firstly we will calculate the general probability that of P(a < X < b) </em>

       P(a < X < b) =  \int_{a}^{b} \frac{2}{x^{3}} dx = 2\int_{a}^{b} x^{-3} dx

                            = 2[ \frac{x^{-3+1} }{-3+1}]^{b}_a   dx    { Because \int_{a}^{b} x^{n} dx = [ \frac{x^{n+1} }{n+1}]^{b}_a }

                            = 2[ \frac{x^{-2} }{-2}]^{b}_a = \frac{2}{-2} [ x^{-2} ]^{b}_a

                            = -1 [ b^{-2} - a^{-2}  ] = \frac{1}{a^{2} } - \frac{1}{b^{2} }

a) Now P(X < 5) = P(1 < X < 5)  {because x > 1 }

     Comparing with general probability we get,

     P(1 < X < 5) = \frac{1}{1^{2} } - \frac{1}{5^{2} } = 1 - \frac{1}{25} = 0.96 .

b) P(X > 8) = P(8 < X < ∞) = 1/8^{2} - 1/∞ = 1/64 - 0 = 0.016

c) P(6 < X < 10) = \frac{1}{6^{2} } - \frac{1}{10^{2} } = \frac{1}{36} - \frac{1}{100 } = 0.018 .

d) P(x < 6 or X > 10) = P(1 < X < 6) + P(10 < X < ∞)

                                = (\frac{1}{1^{2} } - \frac{1}{6^{2} }) + (1/10^{2} - 1/∞) = 1 - 1/36 + 1/100 + 0 = 0.982

e) We have to find x such that P(X < x) = 0.75 ;

               ⇒  P(1 < X < x) = 0.75

               ⇒  \frac{1}{1^{2} } - \frac{1}{x^{2} } = 0.75

               ⇒  \frac{1} {x^{2} } = 1 - 0.75 = 0.25

               ⇒  x^{2} = \frac{1}{0.25}   ⇒ x^{2} = 4 ⇒ x = 2  

Therefore, value of x such that P(X < x) = 0.75 is 2.

8 0
3 years ago
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