Parallel lines will have the same slope, but different y int
y = -3/2x + 8....slope = -3/2....y int = 8
(I) 3x + 2y = 10
2y = -3x + 10
y = -3/2x + 5....slope = -3/2, y int = 5....this IS parallel
(II) 2x - 3y = 9
-3y = -2x + 9
y = 2/3x - 3...slope = 2/3, y int = -3....is not parallel
(III) 6x + 4y = 28
4y = -6x + 28
y = -3/2x + 7...slope = -3/2, y int = 7....this IS parallel
(IV) 3x - 2y = 8
-2y = -3x + 8
y = 3/2x - 4...slope = 3/2...y int = -4...this is not parallel
solution is : I and III
Answer:
Step-by-step explanation:
i got band and theres nothing below
Answer:
-130356
Step-by-step explanation:
solve for bracket first
4-21730 = -21726 then multiply by 6 =
-130356
Take 3 4 5 3 4 5 6 5 4 3 2 3 4 5 6 4 8 4 3 2 and add them all together
=83
Now you divide 83 by the number of terms in the sample set, which is 20.
83/20 = 4.15
For rounding to the nearest tenth, look at the hundredths space, which is 5. Since it is 5 or higher, round the tenths up one.
final answer= 4.2
Base case: if <em>n</em> = 1, then
1² - 1 = 0
which is even.
Induction hypothesis: assume the statement is true for <em>n</em> = <em>k</em>, namely that <em>k</em> ² - <em>k</em> is even. This means that <em>k</em> ² - <em>k</em> = 2<em>m</em> for some integer <em>m</em>.
Induction step: show that the assumption implies (<em>k</em> + 1)² - (<em>k</em> + 1) is also even. We have
(<em>k</em> + 1)² - (<em>k</em> + 1) = <em>k</em> ² + 2<em>k</em> + 1 - <em>k</em> - 1
… = (<em>k</em> ² - <em>k</em>) + 2<em>k</em>
… = 2<em>m</em> + 2<em>k</em>
… = 2 (<em>m</em> + <em>k</em>)
which is clearly even. QED