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3 years ago

Cosx=4/5 what is sin2x cos2x and tan2x

Mathematics

1 answer:

earnstyle [38]3 years ago

4 0

Answer:

-24/5

Step-by-step explanation:

The solution to the problem is as follows:

cscx < 0 means 1/sinx < 0, or sinx < 0.

sinx = -3/5 because you're dealing with a 3-4-5 triangle, and we established

sinx is negative.

sin2x = 2sinxcosx = 2*-3/5*4/5 = -24/25

cos(2x) = cos^2(x) - sin^2(x) = 16/25 - 9/25 = 5/25 = 1/5

tan2x = sin2x / cos2x = -24/5

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Fiona, Dan and Stephen share £66 in a ratio 1:3:2. How much money does each person get?

FinnZ [79.3K]

Answer:

£11, £33, £22

Step-by-step explanation:

F:D:S= 1:3:2

x+3x+2x= 66
6x=66
x= £11

Fiona £11

Dan £33

Stephen £22

4 0

3 years ago

Plz help! Question in picture. What is the slope?

slava [35]

Answer:

Step-by-step explanation:

To find the slop, use (rise/run)

The y goes from 0 to 7/3

The x goes from 0 to 1/3

This means it would be (7/3)/(1/3)

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3 years ago

A bin of 50 manufactured parts contains 3 defective parts and 47 non-defective parts. A sample of size 6 parts is selected from

lyudmila [28]

Answer:

535,095 different samples of size six that contain exactly 2 defective parts.

0.0337 = 3.37% probability that a sample contains exactly 2 defective parts.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

As the order of the parts is not important, the combinations formula is used to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

How many different samples are there of size six that contain exactly 2 defective parts?

2 defective from a set of 3, and 4 non-defective from a set of 47. So

$D = C_{3,2}*C_{47,4} = \frac{3!}{2!1!}*\frac{47!}{4!43!} = 535095$

535,095 different samples of size six that contain exactly 2 defective parts.

What is the probability that a sample contains exactly 2 defective parts?

The total number of samples is:

$T = C_{50,6} = \frac{50!}{6!44!} = 15890700$

Then...

$p = \frac{D}{T} = \frac{535095}{15890700} = 0.0337$

0.0337 = 3.37% probability that a sample contains exactly 2 defective parts.

8 0

3 years ago

Let f(x)=ex.

Klio2033 [76]

Answer:

Not sure if this is exactly the same,but hopefully it answers your questions.

Download pdf

4 0

3 years ago

PLEASE HELP (marking brainliest)

stich3 [128]

Answer:

28 free thows

Step-by-step explanation:

35÷5=7

4×7=28

6 0

3 years ago

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