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2 years ago

Cosx=4/5 what is sin2x cos2x and tan2x

Mathematics

1 answer:

earnstyle [38]2 years ago

4 0

Answer:

-24/5

Step-by-step explanation:

The solution to the problem is as follows:

cscx < 0 means 1/sinx < 0, or sinx < 0.

sinx = -3/5 because you're dealing with a 3-4-5 triangle, and we established

sinx is negative.

sin2x = 2sinxcosx = 2*-3/5*4/5 = -24/25

cos(2x) = cos^2(x) - sin^2(x) = 16/25 - 9/25 = 5/25 = 1/5

tan2x = sin2x / cos2x = -24/5

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Which value of x makes the numerical sentence true? 25^ 1/2 × 5 ^–3 = 5 ^x

Elenna [48]

5^-3=0.008
1/2=0.5
0.5*0.008=0.004
5/0.004=1250

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3 years ago

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Can someone help me on this plz thankyou!!

kipiarov [429]

G(x) is a translation of f(x) 5 units up
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2 years ago

Simplify the following expression as much as you can use exponential properties. (6^-2)(3^-3)(3*6)^4

gtnhenbr [62]

Answer:

Simplifying the expression $(6^{-2})(3^{-3})(3*6)^4$ we get $\mathbf{108}$

Step-by-step explanation:

We need to simplify the expression $(6^{-2})(3^{-3})(3*6)^4$

Solving:

$(6^{-2})(3^{-3})(3*6)^4$

Applying exponent rule: $a^{-m}=\frac{1}{a^m}$

$=\frac{1}{(6^{2})}\frac{1}{(3^{3})}(18)^4\\=\frac{(18)^4}{6^{2}\:.\:3^{3}} \\$

Factors of $18=2\times 3\times 3=2\times3^2$

Factors of $6=2\times 3$

Replacing terms with factors

$=\frac{(2\times3^2)^4}{(2\times 3)^{2}\:.\:3^{3}} \\=\frac{(2)^4\times(3^2)^4}{(2)^2\times (3)^{2}\:.\:3^{3}} \\$

Using exponent rule: $(a^m)^n=a^{m\times n}$

$=\frac{(2)^4\times(3)^8}{(2)^2\times (3)^{2}\:.\:3^{3}} \\=\frac{2^4\times 3^8}{2^2\times 3^{2}\:.\:3^{3}}$

Using exponent rule: $a^m.a^n=a^{m+n}$

$=\frac{2^4\times 3^8}{2^2\times 3^{2+3}}\\=\frac{2^4\times 3^8}{2^2\times 3^{5}}$

Now using exponent rule: $\frac{a^m}{a^n}=a^{m-n}$

$=2^{4-2}\times 3^{8-5}\\=2^{2}\times 3^{3}\\=4\times 27\\=108$

So, simplifying the expression $(6^{-2})(3^{-3})(3*6)^4$ we get $\mathbf{108}$

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2 years ago

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Nimfa-mama [501]

Nothing crazy here, just a matter of figuring out the limits of integration.

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Anon25 [30]

Answer:

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Step-by-step explanation:

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