Answer:
Step-by-step explanation:
Consider, in ΔRPQ,
RP = R (Radius of larger circle)
PQ = r (radius of smaller circle)
We have to find, RQ, by Pythagoras theorem,
RP² = PQ²+RQ²
R² = r²+RQ²
RQ² = R²-r²
RQ = √(R²-r²
Now, as RQ & QS both are tangents of the smaller circle, their lengths must be equal. so, RS = 2 × RQ
RS = 2√(R²-r²)
Answer:
23 r1
Step-by-step explanation:
23 R 1
28/653
-56
93 bring down three
92
=1 which is remainder
28*2=56
28*3=92
Answer:
it is infinitive solutions because if you do the work you'll find that its infinite solutions...bye rate 1 thx rate more if you think i was wrong just kidding ik im right just say if its helpful ...thx
Step-by-step explanation:
