I RLLY NEED HELP PLS

a carpenter is making a circular table top with circumference 4.5 what is the radius of the table top in centmetres

sineoko [7]

That's going to depend completely on the unit of
the 4.5 which, sadly, you have not mentioned.

3 0

3 years ago

Read 2 more answers

Write the equations of the horizontal and vertical lines through the given point.

Tema [17]

#7

vertical x = 5

and

horizontal y=6

#8

vertical x = -2

and

horizontal y=-3

btw

#10: -10x - 3

#11: -5x -3

4 0

4 years ago

I NEED HELP FAST PLEASE

Stells [14]

Answer:

The second and fourth option

Step-by-step explanation:

In order for two lines to be perpendicular they must intercept each other and their slope must be the opposite inverse; ex: $\frac{-1}{4}$ the negative inverse is 4 (multiplying by -1 and flipping the fraction)

8 0

3 years ago

Find the LCD of 3/5 and 1/6.

Harrizon [31]

Question 1:

We have to find the LCD of $\frac{3}{5}$ and $\frac{1}{6}$

LCD is the least common denominator is the lowest common multiple of the denominators of a set of fractions.

Here the denominators are 5 and 6.

So, we will find the LCM of 5 and 6

5 = $5 \times 1$

6 = $2 \times 3$

LCM of 5 and 6 = $2 \times 3 \times 5$

= 30

Therefore, the LCD of these numbers is 30.

Question 2:

We have to find the difference between $\frac{3}{7}$ and $\frac{1}{14}$ .

Difference = $\frac{3}{7}- \frac{1}{14}$

LCM of 7 and 14 is 14

Therefore, difference = $\frac{6-1}{14}$

= $\frac{5}{14}$

Question 3:

Amount of brown sugar used by Sandy = $\frac{1}{3}$

Amount of sugar increased by Sandy = $\frac{2}{9}$

Total amount of Sugar used by Sandy = $\frac{1}{3}+\frac{2}{9}$

LCM of 3 and 9 is 9.

Total amount of Sugar used = $\frac{3+2}{9}$

= $\frac{5}{9}$ cup

Question 4:

Let the number which should be added to $\frac{2}{15}$ to make the sum greater than $\frac{1}{2}$ be 'x'

So, $\frac{2}{15}+x >\frac{1}{2}$

$x > \frac{1}{2}-\frac{2}{15}$

LCM of 2 and 15 is 30.

$x>\frac{15-4}{30}$

$x>\frac{11}{30}$

So, the number is $\frac{11}{30}$

Question 5:

We have to identify the set of mixed numbers has a difference less than 1.

Set 1: $1 \frac{2}{9}$ and $1 \frac{1}{9}$

Difference = $1 \frac{2}{9}-1 \frac{1}{9}$

= $\frac{11}{9}- \frac{10}{9}$

= $\frac{1}{9}$

This set has difference less than 1.

Set 2:

$3 \frac{4}{7}$ and $2 \frac{1}{7}$

Difference = $3 \frac{4}{7}-2 \frac{1}{7}$

= $\frac{25}{7}- \frac{15}{7}$

= $\frac{10}{7}$

This set does'not have difference less than 1.

Set 3:

$2 \frac{4}{5}$ and $1 \frac{1}{3}$

Difference = $2 \frac{4}{5}-1 \frac{1}{3}$

= $\frac{14}{5}- \frac{4}{3}$

= $\frac{42-20}{15}$

= $\frac{22}{15}$

This set does'not have difference less than 1.

Set 4:

$2 \frac{7}{9}$ and $1 \frac{1}{3}$

Difference = $2 \frac{7}{9}-1 \frac{1}{3}$

= $\frac{25}{9}- \frac{4}{3}$

= $\frac{13}{9}$

This set does'not have difference less than 1.

7 0

3 years ago

Ln 5 - ln a + 6 ln b- 6 ln c, please condense this logarithm, I fear I messed it up

NemiM [27]

$Use:\\lnx-lny=ln(\frac{x}{y})\\\\lnx+lny=ln(x\cdot y)\\\\lnx^y=y\cdot lnx$

$ln5-lna+6lnb-6lnc=ln\frac{5}{a}+lnb^6-lnc^6=ln\frac{5}{a}+ln\frac{b^6}{c^6}\\\\=\boxed{ln\frac{5b^6}{ac^6}}\\\\\\where:a > 0;\ b > 0\ and\ c > 0$

8 0

3 years ago