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disa [49]
2 years ago
13

A circle has a radius of 5.4 m. what is the exact length of an arc formed by a central angle measuring 60°? enter your answer in

the box. express your answer using π . m
Mathematics
1 answer:
velikii [3]2 years ago
3 0

The length of the arc of the circle with a radius of 5.4 m and the central angle measuring 60° is 5.655 meters.

<h3>What is the Length of an Arc?</h3>

The length of an arc is given by the formula,

\rm{ Length\ of\ an\ Arc = 2\times \pi \times(radius)\times\dfrac{\theta}{360}

where

θ is the angle, which arc creates at the centre of the circle in degree.

The length of the arc of the circle with a radius of 5.4 m and the central angle measuring 60° can be written as

\text{Length of the Arc} = 2\pi r \dfrac{\theta}{360}

                            = 2 \times \pi \times 5.4 \times \dfrac{60}{360}\\\\=5.655\rm\ m

Hence, the length of the arc of the circle with a radius of 5.4 m and the central angle measuring 60° is 5.655 meters.

Learn more about Lenght of the Arc:

brainly.com/question/1577784

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Crank

Answer:

1.204119982655924780854955578898‬

Step-by-step explanation:

7 0
3 years ago
Vectors: Find the vector from the point A=(−1,−7,3) to the point B=(3,−2,9).
devlian [24]

Answer:

\overrightarrow {AB} = (4,5,6)

1. 〈x,y,z〉=〈−1,−7,3〉+t〈−4,−5,−6〉 F

2. 〈x,y,z〉=〈−1,−7,3〉+t〈3,−2,9〉 F

3. 〈x,y,z〉=〈−1,−7,3〉+t〈4,5,6〉 T

4. 〈x,y,z〉=〈3,−2,9〉+t〈−1,−7,3〉 F

5. 〈x,y,z〉=〈3,−2,9〉+t〈4,5,6〉 F

Step-by-step explanation:

The vector AB is the vectorial difference between point A and B, that is:

\overrightarrow {AB} = \vec B - \vec A

Given that \vec A = (-1,-7,3) and \vec B = (3,-2,9), the vector AB is:

\overrightarrow {AB} = (3,-2,9)-(-1,-7,3)

\overrightarrow{AB} = (3-(-1),-2-(-7),9-3)

\overrightarrow {AB} = (4,5,6)

The vectorial equation of the line is represented by:

\langle x, y, z\rangle = \vec A + t \cdot \overrightarrow {AB}

Where t is the parametric variable, dimensionless. Given that \vec A = (-1,-7,3) and \overrightarrow {AB} = (4,5,6)

\langle x,y,z \rangle = \langle -1,-7,3 \rangle + t\cdot \langle 4,5,6 \rangle

Finally, the list of questions are now checked:

1. 〈x,y,z〉=〈−1,−7,3〉+t〈−4,−5,−6〉 F

2. 〈x,y,z〉=〈−1,−7,3〉+t〈3,−2,9〉 F

3. 〈x,y,z〉=〈−1,−7,3〉+t〈4,5,6〉 T

4. 〈x,y,z〉=〈3,−2,9〉+t〈−1,−7,3〉 F

5. 〈x,y,z〉=〈3,−2,9〉+t〈4,5,6〉 F

4 0
2 years ago
Quadrilateral $abcd$ is a trapezoid with $ab$ parallel to $cd$. we know $ab = 20$ and $cd = 12$. what is the ratio of the area o
alekssr [168]
Draw a diagram to illustrate the problem as shown below.

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A₁ = (1/2)*20*h = 10h

The area of trapezoid abcd is
A₂ = (1/2)*(20+12)*h = 16h

The ratio A₁/A₂ is
A₁/A₂ = (10h)/(16) = 5/8

Answer:
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1/2r + 4= 3/4r - 3/2
ikadub [295]
<span>1/2r + 4= 3/4r - 3/2

1/2 = 2/4
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re-write
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      r = (-4 3/4) / (-1/4)
      r =(-4 3/4) * (-4)
      r = 76/4
      r = 19</span>
7 0
3 years ago
Read 2 more answers
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