−10(9c−7c+8)−8c pls help
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The parents could have 3 boys and 3 girls in 400 ways
<h3>How to determine the number of ways?</h3>The given parameters are
Children, n = 6
Boys, r = 3
Girls, r =3
The number of combination is:
So, we have:
Apply the combination formula
This gives
Ways = 400
Hence, the parents could have 3 boys and 3 girls in 400 ways
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Answer:
Step-by-step explanation:
Given: ∠PTQ ≅ ∠STR and TP, TQ, TR and TS are radii of the circle.
If two angle are equal, then they are equal in size and their measurements are equal.
IF ∠PTQ ≅ ∠STR then they are also equal in their measurements.
Now, In ΔPTQ and ΔSTR
∠PTQ ≅ ∠STR (vertically opposite angle)
(Radius of the circle are equal and congruent in length)
(Radius of the circle)
∴ ΔPTQ ≅ ΔSTR (SAS postulate)
∴ (corresponding sides of congruent triangle are equal and congruent).