This is equivalent to:

(2.2533/2.59)(10^8/10^4)

(0.87)(10^4) which is:

0.87X10^4 which is equal to:

0.87X10000 which is equal to:

8.7X1000 and since 1000=10^3 we can say:

8.7X10^3

6 0

2 years ago

Find the standard equation of the parabola that satisfies the given conditions. Also, find the length of the latus rectum of eac

lakkis [162]

Answer:

The standard parabola

y² = -18 x +27

Length of Latus rectum = 4 a = 18

Step-by-step explanation:

<u><em>Explanation:-</em></u>

Given focus : (-3 ,0) ,directrix : x=6

Let P(x₁ , y₁) be the point on parabola

PM perpendicular to the the directrix L

SP² = PM²

(x₁ +3)²+(y₁-0)² = $(\frac{x_{1}-6 }{\sqrt{1} } )^{2}$

x₁²+6 x₁ +9 + y₁² = x₁²-12 x₁ +36

y₁² = -18 x₁ +36 -9

y₁² = -18 x₁ +27

The standard parabola

y² = -18 x +27

Length of Latus rectum = 4 a = 4 (18/4) = 18

5 0

3 years ago

Answer asap which equation could have been used to create this function table?

stiks02 [169]

C. y= x + 4
If you plug it in
1 + 4=5
6 + 4 = 10
8 + 4 = 12
and so forth

7 0

3 years ago