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statuscvo [17]
3 years ago
8

A box is to be constructed with a rectangular base and a height of h cm. The length, l, of the box is 10 cm, and the width, w, i

s twice the height. Which quadratic equation best models the volume of the box?
V = lwh

a)V = 20h
b)V = 20h2
c)V = 100h
d)V = 100h2
Mathematics
1 answer:
77julia77 [94]3 years ago
6 0

Answer:

The Quick answer is B.

Step-by-step explanation:

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The equation y= 2(x+1)^2 has one real root and that is x=-1.

What is real roots of the equation?

    We are aware that when we resolve a linear or quadratic equation, we always arrive at the value variable of the equation, or, to put it another way, we always locate the equation's solution. This "solution" is what we refer to as the real roots. For instance, when the equation X^2-7x+12=0 is solved, the actual roots are 3 and 4.

Here given,

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PLEASE ANSWER ASAP FOR BRAINLEST!!!!!!!!!!!!!!!!!!!
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$4x-5$ is less than 25$

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How do you describe the function of a graph?
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1 year ago
Steel loading ramps are used to load a lawn mower onto a truck bed 37.5 inches above the ground. If the ramp make a 30° angle wi
scoray [572]

Answer:

6.25 feet.

Step-by-step explanation:

Please find the attachment.

Let L be the length of the ramp in feet.  

We have been given that steel loading ramps are used to load a lawn mower onto a truck bed 37.5 inches above the ground. The ramp make a 30° angle with the ground.

We can see from our attachment that ramp and truck bed forms a right triangle with ground. The truck bed is opposite side and length of ramp is hypotenuse of our given angle.

Since we know that Sine relates the opposite and hypotenuse of a right triangle, so we will use Sine to solve for L.

\text{Sine}=\frac{\text{Opposite}}{\text{Hypotenuse}}

Upon substituting our given values in above formula we will get,

\text{Sin(30)}=\frac{37.5}{L}

L=\frac{37.5}{\text{Sin(30)}}

L=\frac{37.5}{0.5}

L=75

Therefore, the length of the ramp is 75 inches.

Let us convert the length of ramp in feet.

1 feet = 12 inches.

\text{75 inches}=\frac{75\text{ inches}}{\frac{12\text{ inches}}{\text{feet}}}

\text{75 inches}=\frac{75\text{ inches}}{12}\times \frac{\text{ feet}}{\text{inches}}

\text{75 inches}=\frac{75}{12}\times\text{ feet}

\text{75 inches}=6.25\text{ feet}

Therefore, the length of the ramp is 6.25 feet.

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