Help 8th grade need answers quick

Mathematics

1 answer:

yaroslaw [1]3 years ago

5 0

Answer:

with what nothings there

Step-by-step explanation:

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Solve the equation 6(y+1.5)= -18. what is the value of y? y=

asambeis [7]

Answer:

y = -4.5

Step-by-step explanation:

6 0

3 years ago

Nicole earn 40,768 per year what are her weekly gross earnings

marissa [1.9K]

40,768/52 (weeks per yr)= 784

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3 years ago

12/11-(-2/3)=?????????????????????????????????????????

sveta [45]

Answer:

58/33

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

2(b+3c) equivalent expressions Options: 3(b+2c) (b+3c) +(b+3c) None of the above

Lana71 [14]

2(b + 3c) → We first need to simplify this.

Simplify.

2b + 6c

1st Option :

3(b + 2c)

Simplify.

3b + 6c

This is INCORRECT, as it is not equal to 2b + 6c.

2nd Option :

(b + 3c) + (b + 3c)

Simplify.

2b + 6c

This is CORRECT because 2b+6c = 2b+6c

(b + 3c) + (b + 3c) → Answer

~Hope I helped!~

5 0

3 years ago

Find the volume of the following solid. Using cylindrical coordinates

Reika [66]

In cylindrical coordinates, the equations of the surfaces become

$z = 4 - 4r^2 \\\\ z = (r^2)^2 - 1 = r^4 - 1$

These surfaces intersect on the cylinder of radius 1 with cross sections parallel to the x,y-plane:

$4 - 4r^2 = r^4 - 1 \\\\ \implies r^4 + 4r^2 - 5 = (r-1)(r+1)(r^2+5) = 0 \\\\ \implies r=1$

Then in cylindrical coordinates, the volume of the space bounded by these surfaces is

$\displaystyle \int_0^{2\pi}\int_0^1\int_{r^4-1}^{4-4r^2}r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta = 2\pi \int_0^1 \int_{r^4 - 1}^{4-4r^2}r\,\mathrm dz\,\mathrm dr \\\\ = \pi \int_0^1 (4-4r^2)^2 - (r^4-1)^2 \,\mathrm dr \\\\ = \pi \int_0^1 (15-32r^2+18r^4-r^8)\,\mathrm dr = \boxed{\frac{352\pi}{45}}$

7 0

3 years ago