<h2>
Answer:</h2>
<u>By supplementary angle property</u>,
x + 78° = 180°
x = 180° - 78°
<u>x = 102°.</u>
A kilogram of silver contains 5.58×10²⁴ atoms.
<h3>How to determine the parameter</h3>
From the question given above, the following data were obtained:
- 1 mole of silver = 107.9 g
- Number of atoms in 1 mole of silver = 6.02×10²³ atoms.
- Number of atoms in a kilogram of silver is unknown
Now, we shall convert 1 kg of silver to grams (g).
This can be obtained as follow:
1 kg = 1000g
Therefore, 1 kg of silver is equivalent to 1000g.
Now, let's determine the number of atoms in 1 kg (i.e 1000 g) of silver as follow:
If 107.9 g of silver contains 6.02×10²³ atoms.
Then, 1000 g of silver will contain:
= (1000 × 6.02×10²³) / 107.9
= 5.58×10²⁴ atoms.
Thus, a kilogram of silver contains 5.58×10²⁴ atoms.
Learn more about atoms here:
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Variables: x, y, z (we should multiply them and put them together )
Then coeffitions, we should multiply them
Now put coeffitions before variables:
Answer:
D : 2.15d= 48.00
explanation: if you multiply $2.15 by the amount of days it should equal 48 so to find the amount of day, you have to divide 48.00 by 2.15 (48 ÷ 2.15) to find the maximum of days. the amont of days multiplied by 2.15 should be 48.00
Answer:
if ug ug ug uf yg y gg
Step-by-step explanation:
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