Mean is also known as the average of the numbers. To find the
mean, you have to add up all the numbers and then you have to divide by how
many numbers there are.
For example, this is how you find the mean of the numbers:
59 64 52 41
Add 59, 64, 52, and 41
you get 216.
Divide 216 by 4. You get 54.
So the mean of these numbers if 54.
Hope it helps.
Can you please please choose mine as the brainliest answer
C
Step-by-step explanation:
(88+96+98+90+x)/5=94
Add all the numbers
(372+x)/5=94
Multiply both sides by 5
372+x=470
Subtract 372 from both sides
x=98
Double check:
88+96+98+90+98=470/5=94
Hope that helps
A: 8*9= 72
B: euclidean theorem (35,63) (35,28) (7,28) (7,0) gcf= 7
C: 7(5+9)
To figure out if a graph is a function, you can use this thing called the vertical line test. in case you're unfamiliar, it's basically where you just imagine a vertical line going from left to right on the graph. if it crosses the function in two places, it's incorrect. i suggest looking up a video that shows you a visual representation of the vertical line test if you've never heard of it; it's fairly simple.
A is a function because the graph passes the vertical line test. if you imagine a vertical line and drag it from left to right across the graph, the linear function graphed in choice A does not have two x values at the same spot.
B is not a function. it fails the vertical line test almost immediately: the sideways "U" shapes makes it intersect the vertical line twice in one place.
C is a function. it passes the vertical line test, even though it looks a little strange. at no point does it intersect the vertical line twice.
D is a function. again, it doesn't intersect the vertical line twice.
now, to determine if a function is a one-to-one function, it must also pass the horizontal line test. this means that it doesn't intersect at two points horizontally as well. test that out on choices A, C, and D.
A is a one-to-one function because it doesn't cross in the same place horizontally, either. C and D are one-to-one functions as well.
