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Answer:
I would say if it is a multiple choice
Explanation:
q3 or q5 would be the best ones to pick from in my eyes.
You're substracting one from the variable "exponent" with every iteration of the loop, and you told it to break out of the loop once "exponent" is 0, therefore, it's always going to end up as 0 at the end.
If you want to keep the input from the user, then declare another variable like "counter" and assign the value of "exponent" to it and use it for the loop
Or even better, do this for the loop:
for(int i = 0; i < exponent; i++)
{
//Code here
}
Answer:
The development of diffusion dialysis for alkali separation
Explanation:
Diffusion Dialysis (DD) gives another option, perfect and planned strategy for corrosive and antacid recuperation. The most out standing preferences of DD are the perfect nature, low utilization of vitality, low establishment and working expense. Moreover, the integrations of DD (especially for corrosive recuperation frameworks) with other techniques can build the handling ability and effectiveness, so that the acids (even with low fixation) and the metal salts can be effectively recouped.
Different parameters will impact the proficiency of DD, such as film properties (particularly water content (WR) and fixed
gathering (CR)), assortment and grouping of waste arrangement, and the activity conditions (activity temperature, the stream rate, stream proportion). As needs be, critical contrasts have been accounted for for various DD frameworks: the "salt impact" is clear in the
HCl + chlorides DD frameworks, while in the H2SO4 + sulfates DD systems, the "salt impact" almost can't be watched; low retention
furthermore, high diffusivity in film are constantly seen in the solid corrosive arrangements, while in the powerless corrosive arrangement, the patterns are simply inverse; the "water assimilation" is moderately increasingly evident in the soluble base feed arrangement than that in the solid corrosive feed, and consequently the effectiveness of soluble base recuperation is lower.
Answer:
a. 32
Explanation:
Form the above code
{ *yPtr +=3 ;
*zPtr,
c+=3;
func(c,bPTR,&c);
the a=*bPtr c
return value 32 after execution
