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JulsSmile [24]
3 years ago
6

Studies indicate that about 10 percent of polar bears weigh more than 1,000 pounds. A biologist studying the bears thinks that p

ercent might be too high. From a random sample of polar bears, the biologist found only 8 percent of the sample weighing over 1,000 pounds. Which of the following is the most appropriate method for the biologist’s study?
A one-sample z
-test for a sample proportion
A one-sample z -test for a sample proportion

A one-sample z
-test for a population proportion
A one-sample z -test for a population proportion

A one-sample z
-test for a difference in population proportions
A one-sample z -test for a difference in population proportions

A two-sample z
-test for a difference in sample proportions
A two-sample z -test for a difference in sample proportions

A two-sample z
-test for a difference in population proportions
Mathematics
1 answer:
Usimov [2.4K]3 years ago
3 0

Answer: B) A one sample Z test for a population proportion

Step-by-step explanation: Trust me bro.

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Answer:

(1-0.01p)/n

Step-by-step explanation:

Mathematically;

Percentage of student playing at least one sport = 100% - Percentage of students playing no sport

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So, to find this in n 7th graders

we have;

(100-p)/100 * n

= 100-P/100n = 1/n - P/100n

= 1/n - 0.01p/n

= (1-0.01p)/n

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Step-by-step explanation:

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B I hope this help :)

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melisa1 [442]
3 by 21 because 1/4 of 12 is is 3
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