A = amount invested at 4%.
b = amount invested at 9%.
we know the total amount invested was $26500, thus 
a + b = 26500.
whatever% of anything is just (whatever/100) * anything.
how much is 4% of a?  well, is just (4/100) * a, or 
0.04a.
how much is 9% of b?  well, is just (9/100) * b, or 
0.09b.
we know the interest yielded for both amounts adds up to $1510, thus 
0.04a + 0.09b = 1510.

how much was invested at 9%?  well, b = 26500 - a.
 
        
        
        
It's an easy problems. what equations are you trying to find?
        
             
        
        
        
Answer:

Step-by-step explanation:
change to improper

this gives us

final answer
plz mark as brainliest
  
        
                    
             
        
        
        
Answer:
Step-by-step explanation:
The picture is below of how to separate this into 2 different regions, which you have to because it's not continuous over the whole function. It "breaks" at x = 2. So the way to separate this is to take the integral from x = 0 to x = 2 and then add it to the integral for x = 2 to x = 3. In order to integrate each one of those "parts" of that absolute value function we have to determine the equation for each line that makes up that part. 
For the integral from [0, 2], the equation of the line is -3x + 6;
For the integral from [2, 3], the equation of the line is 3x - 6.
We integrate then:
 and
    and
 sorry for the odd representation; that's as good as it gets here!
  sorry for the odd representation; that's as good as it gets here!
Using the First Fundamental Theorem of Calculus, we get:
(6 - 0) + (-4.5 - (-6)) = 6 + 1.5 = 7.5
 
        
             
        
        
        
2(7/2)^x = 49/2
Divide both sides by 2:
(7/2)^x = 49/4
I notice that 49/4 can be rewritten as (7/2)^2, so we now have:
(7/2)^x = (7/2)^2
The only way for this to be true is if x = 2.  Thus, we are done.