The percentage of tardiness among the 102 pupils is 2.94.
<h2>Calculation of the percentage</h2>
According to the query,
Course A: Total number of students = 102
Number of tardy students = 3
Percent of students tardy in course A = (number of tardy students/total
number of students) * 100
=(3/102)*100
= 2.941
≈2.94
In case of course B: Total number of students = 85 & tardy student = 5
So, the percent of tardy student = (5/85)*100 = 5.88 %
Therefore, it is concluded that the percentage of student tardiness in course A is 2.94.
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<h3>Answer: so 3 goes into 12 4 times and 5 times 4 is 20.
Step-by-step explanation:
</h3>
Answer:
The tree is 16.25 m tall.
Step-by-step explanation:
Attached is a diagram that better explains the problem.
From the diagram we see that the distance between the top of the tree and the line of sight of the observer is x.
To find the height of the tree, we need to first find x and then add it to the height of the observers line of sight from the ground.
Using SOHCAHTOA trigonometric function:
tan(20) = x/39.2
=> x = 39.2 * tan(20)
x = 39.2 * 0.364
x = 14.27m
Hence, the height of the tree is:
(14.27 + 1.98)m
16.25m
The tree is 16.25 m tall.
Answer:
(-2,3)
Step-by-step explanation:
Step 1. Isolate x for 3x + 5y = 9
3x + 5y - 5y = 9 - 5y
3x = 9 - 5y
3x/3 = 9/3 - 5y/3
x= (9-5y)/3
Step 2. Simplify
-3*((9-5y)/3) + 3y = 15
-3*((9-5y)/3) = 9 - 5y = -(-5 + 9) + 3y
-9+5y+3y
-9+8y = 15
Step 3 Isolate y for -9+8y=15
-9+8y+9=15+9
8y=24
8y/8 = 24/8
y=3
Step 4 Substitute y = 3
x = (9-5*3)/3
-(6/3) = (-2)
x = -2