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Novosadov [1.4K]
3 years ago
14

X+5+x11=10 Solve for X and show the work please!

Mathematics
1 answer:
kenny6666 [7]3 years ago
6 0

Answer:

x=5/12

Step-by-step explanation:

Simplify left side by adding 11x+x

12x+5=10

Get x alone on left side by subtracting 5 on both sides

12x=5

Get X alone by dividing both sides by 12

x=5/12

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Two sides of a triangle measure 2x – 4 and 7x – 2 units, respectively. Which of these is a possible length for the third side of
lutik1710 [3]
The answer here would be 6x. 
8 0
3 years ago
.872 to scientific notation
Crazy boy [7]

Answer:

8.72×10²

Step-by-step explanation:

  1. 8.72×10²=872
3 0
3 years ago
Find the distance and midpoint for the points (3,4) and (19, 16).
Goryan [66]

Given parameters:

   Coordinates of the points =  (3,4) and (19, 16)

Unknown:

The distance between the points = ?

The midpoint  = ?

Solution:

  The distance between two points can be mathematically solved using;

    D  = \sqrt{(x_{2} - x_{1})^{2}  + (y_{2} - y_{1})^{2}  }

 where  x₁  = 3, x₂  = 19  and y₁  = 4, y₂  = 16

Input the parameters and solve;

   D  = \sqrt{(19 - 3)^{2} + (16 - 4)^{2}  }   = 20

Midpoint;

    The expression is given as;

     x_{m} , y_{m}  = \frac{x_{1} + x_{2}  }{2}  , \frac{y_{1} + y_{2}  }{2}

         input the parameters and solve;

                   = \frac{3 + 19}{2}  , \frac{4 + 16}{2}

                   = 11 , 10

The midpoint is (11, 10)

 

8 0
3 years ago
Can any one help me plz 27=9h
abruzzese [7]
H=3 because 27 divided by 9 is 3
5 0
3 years ago
Read 2 more answers
Given the following discrete uniform probability distribution, find the expected value and standard deviation of the random vari
katovenus [111]

The expected value is

E[X]=\displaystyle\sum_xx\,P(X=x)=\frac1{11}\sum_{x=0}^{10}x=\dfrac{0+1+\cdots+9+10}{11}=\dfrac{55}{11}=\boxed{5}

The standard deviation is the square root of the variance, which is

V[X]=E[(X-E[X])^2]=E[X^2]-E[X]^2

where

E[X^2]=\displaystyle\sum_xx^2\,P(X=x)=\frac1{11}\sum_{x=0}^{10}x^2=\dfrac{0^2+1^2+\cdots+9^2+10^2}{11}=\dfrac{385}{11}=35

so that

V[X]=35-5^2=10

making the standard deviation

\sqrt{V[X]}=\sqrt{10}\approx\boxed{3.16}

3 0
3 years ago
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