Solve equation for y.
5x - y = 3
-y = -5x + 3
y = (-5x + 3)/(-1)
y = 5x - 3
The slope for this equation is 5.
The slope of the equation we want is the negative reciprocal of 5.
Let m = slope of equation we want.
m = -1/5
We are given the point (10,4).
Plug both into the point-slope formula.
y - 4 = (-1/5)(x - 10)
y - 4 = (-1/5)x + 2
y = (-1/5)x + 2 + 4
The equation we want is
y = (-1/5)x + 6
Did you follow?
Answer:
y = -2
Step-by-step explanation:
First, we subtract 2y on both sides:
-24 = 12y
Then, we divide 12 on both sides:
y = -2
And we're done ^^ hope this helps!
Answer:
The correct option is A.
Step-by-step explanation:
Domain:
The expression in the denominator is x^2-2x-3
x² - 2x-3 ≠0
-3 = +1 -4
(x²-2x+1)-4 ≠0
(x²-2x+1)=(x-1)²
(x-1)² - (2)² ≠0
∴a²-b² =(a-b)(a+b)
(x-1-2)(x-1+2) ≠0
(x-3)(x+1) ≠0
x≠3 for all x≠ -1
So there is a hole at x=3 and an asymptote at x= -1, so Option B is wrong
Asymptote:
x-3/x^2-2x-3
We know that denominator is equal to (x-3)(x+1)
x-3/(x-3)(x+1)
x-3 will be cancelled out by x-3
1/x+1
We have asymptote at x=-1 and hole at x=3, therefore the correct option is A....
When you reflect a point across the x-axis, the x-coordinate remains the same, but the y-coordinate is transformed into its opposite (its sign is changed). If you forget the rules for reflections when graphing, simply fold your paper along the x-axis (the line of reflection) to see where the new figure will be located.
Answer:
The radius of the volleyball is 8.3 inches
Step-by-step explanation:
Given
![r = \sqrt{\frac{3v}{4\pi}}](https://tex.z-dn.net/?f=r%20%3D%20%5Csqrt%7B%5Cfrac%7B3v%7D%7B4%5Cpi%7D%7D)
![v = 288](https://tex.z-dn.net/?f=v%20%3D%20288)
Required
Determine the value of r
To do this, we simply substitute 288 for v and 3.14 for π in the given equation.
This gives
![r = \sqrt{\frac{3v}{4\pi}}](https://tex.z-dn.net/?f=r%20%3D%20%5Csqrt%7B%5Cfrac%7B3v%7D%7B4%5Cpi%7D%7D)
![r = \sqrt{\frac{3 * 288}{4 * 3.14}}](https://tex.z-dn.net/?f=r%20%3D%20%5Csqrt%7B%5Cfrac%7B3%20%2A%20288%7D%7B4%20%2A%203.14%7D%7D)
![r = \sqrt{\frac{864}{12.56}}](https://tex.z-dn.net/?f=r%20%3D%20%5Csqrt%7B%5Cfrac%7B864%7D%7B12.56%7D%7D)
![r = \sqrt{68.7898089172}](https://tex.z-dn.net/?f=r%20%3D%20%5Csqrt%7B68.7898089172%7D)
![r = 8.29396219651](https://tex.z-dn.net/?f=r%20%3D%208.29396219651)
(Approximated)
Hence;
<em>The radius of the volleyball is 8.3 inches</em>