X/(x^2+3x+2) - 1/((x+2)(x+1))
x/(x^2+3x+2) - 1/(x^2+3x+2)
(x - 1)/(x^2+3x+2)
Answer: Choice D
0.008 = eight thousandths
Hope it helps
Answer: 
We have something in the form log(x/y) where x = q^2*sqrt(m) and y = n^3. The log is base 2.
===========================================================
Explanation:
It seems strange how the first two logs you wrote are base 2, but the third one is not. I'll assume that you meant to say it's also base 2. Because base 2 is fundamental to computing, logs of this nature are often referred to as binary logarithms.
I'm going to use these three log rules, which apply to any base.
- log(A) + log(B) = log(A*B)
- log(A) - log(B) = log(A/B)
- B*log(A) = log(A^B)
From there, we can then say the following:

A dialation produces a shape that is the same shape but different size. so we draw a new triangle about point B where A'B=2AB
so B and B' are the same and
AB and BC will be parts of the sides. and A' is located on the ray
Answer:
6 meters
Step-by-step explanation:
Th equation to find the diameter of a circle is,
radius * 2.
The radius of the swimming pool is 3, so 3 * 2 is 6.
Hope this helps!!
Let me know if I'm wrong...