Answer:
A = 26
Step-by-step explanation:
sum of students = classA + classB + classC
let's say classA = A, classB = B, and classC = C
A + B + C = 66
class A has five more students than class B, so A = 5 more than B so A = 5+B
class C has 2 less students than class B, so C = 2 less than class B = B -2, so C = B-2
A + B + C = 66
A = 5+B
C = B-2
substitute 5+B for A and B-2 for C in the first equation to limit this to one variable (B)
(5+B) + B + (B-2) = 66
3B + 3 = 66
subtract 3 from both sides to isolate the variable and its coefficient
3B = 63
divide both sides by 3 to solve for B
B = 21
A = 5 + B = 5 + 21 = 26
Answer:
22
Step-by-step explanation:
Given that T is the midpoint of line PQ, segments PT = 5x + 2, and TQ = 7x - 6 that are formed would be equidistant or congruent. PT = TQ.
Therefore:
Let's find the value of x
Rearrange the equation, so that the terms having x would be on your left, while those without x would be on your right.
Divide both sides by -2
Plug in the value of x into the expression, 5x + 2, to find PT.
PT = 5(4) + 2 = 22.
1,2, and 6 are all no’s but everything else is yes I believe
If you are trying to find the slope using only these two points then you should first take note of what your X and Y values are. For instance, 12 & 11 are your X values and -18 & 12 are your Y values. Knowing this you can now find your slope by doing y2-y1/
x2-x1. You will get the fraction -30/1 or -30 which is your slope. Hope that made sense!
24x^2 + 10x = 2x(12x + 5)
