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denis23 [38]
3 years ago
14

rachel bought one double pack of CDs for $20. this is $4 less than 3/4 the cost of a triple pack of CDs. what is the price of a

triple pack of CD's?
Mathematics
1 answer:
Sophie [7]3 years ago
6 0
The price of a triple pack of Cds is $30. 
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Is 4 a factor of 4x+8?
Inga [223]

Answer:

4 is a factor

Step-by-step explanation:

4x+8

4x = 4*x

8 = 4*2

4(x+2)

4 is a factor

7 0
3 years ago
Read 2 more answers
Find the derivative of cscx/3sinx
Neporo4naja [7]
\frac{csc x}{3sinx} =  \frac{1}{3sin ^{2}x }
3 0
3 years ago
Help plz!!!
lara [203]

Answer with explanation:

→→→Function 1

f(x)= - x²+ 8 x -15

Differentiating once , to obtain Maximum or minimum of the function

f'(x)= - 2 x + 8

Put,f'(x)=0

-2 x+ 8=0

2 x=8

Dividing both sides by , 2, we get

x=4

Double differentiating the function

f"(x)= -2, which is negative.

Showing that function attains maximum at ,x=4.

Now,f(4)=-4²+ 8× 4-15

           = -16 +32 -15

          = -31 +32

          =1

→→→Function 2:

f(x) = −x² + 2 x − 3

Differentiating once , to obtain Maximum or minimum of the function

f'(x)= -2 x +2

Put,f'(x)=0

-2 x +2=0

2 x=2

Dividing both sides by , 2, we get

x=1

Double differentiating the function,gives

f"(x)= -2 ,which is negative.

Showing that function attains maximum at ,x=1.

f(1)= -1²+2 ×1 -3

   = -1 +2 -3

  = -4 +2

 = -2

⇒⇒⇒Function 1  has the larger maximum.

6 0
3 years ago
Choose the most appropriate name for the function described below.
olga_2 [115]

Answer: C

Step-by-step explanation:

5 0
3 years ago
By [n][n] we denote the set {1,…,n}. A function f:[m]→[n] is called monotone if f(i) \leq f(j)f(i)≤f(j)whenever i < ji
Dafna11 [192]

Answer:

There are a total of  { 6 \choose 3} = 20 functions.

Step-by-step explanation:

In order to define an injective monotone function from [3] to [6] we need to select 3 different values fromm {1,2,3,4,5,6} and assign the smallest one of them to 1, asign the intermediate value to 2 and the largest value to 3. That way the function is monotone and it satisfies what the problem asks.

The total way of selecting injective monotone functions is, therefore, the total amount of ways to pick 3 elements from a set of 6. That number is the combinatorial number of 6 with 3, in other words

{6 \choose 3} = \frac{6!}{3!(6-3)!} = \frac{720}{6*6} = \frac{720}{36} = 20  

3 0
3 years ago
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