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frozen [14]
3 years ago
9

Ryan would like to copy a list of contacts from a colleague into his personal address book. The list of contacts is

Computers and Technology
1 answer:
Colt1911 [192]3 years ago
5 0

Answer:

He should: Format the text file with comma-separated values and save as CSV file type. ]

Explanation:

hope this helps!

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____ is a practice where a user in enticed by possible rewards and then asked to provide personal information.
Alina [70]
Baiting is the answer
Hope it helped!
8 0
3 years ago
What are three distractions that can prevent a driver from focusing on driving? Explain how a driver can prevent these distracti
DIA [1.3K]

Phone- turn it off

loud music - keep it turned down to a reasonable volume (cause you could start singing and get distracted)

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hope this helps.

8 0
3 years ago
The Springfork Amateur Golf Club has a tournament every weekend. The club president
Lera25 [3.4K]

Answer:

The Python code is given below for each question.

Explanation:

1:

 if __name__ == '__main__':

   f = open('golf.txt', 'w')

   n = int(input("Enter number of players:"))

   for i in range(n):

       name = input("Enter name of player number " + str(i + 1) + ":")

       score = int(input("Enter score of player number " + str(i + 1) + ":"))

       f.write(name + "\n" + str(score) + "\n")

   f.close()

2:

try:

   with open('golf.txt') as r:

       lines = r.readlines()

       for i in range(0, len(lines), 2):

           print("Name:", lines[i].strip())

           print("Score:", lines[i+1].strip())

           print()

except FileNotFoundError:

   print("golf.txt is not found!")

6 0
4 years ago
A computer ________ is two or more computers connected using software and hardware so that they can communicate with each other.
kolbaska11 [484]
The answer would be a network

7 0
3 years ago
The instruction format of a computer is given by one indirect bit, opcode bits, register address bits, immediate operand bits an
oksian1 [2.3K]

Answer:

Following are the answer to this question:

Explanation:

A)

The memory size is 1 Giga Bytes which is equal to 2^{30}

\texttt{Number of address bits    \ \ \ \ \ \ \ \ \ \ \ \ \ \            Number of addresses}\\\\ \ \ \ \ 30  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \                                 2^{30}= 1073741824

B) \texttt{I \ \ \ Opcode  \ \ \ Register address \ \ \  Immediate operand \ \ \    Memory address}\\\\\\\textt{1 \ bit  \  \ \ \ \ \ 128  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \    2 \ bits   \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \   24 \ bits  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  \ \ \ \ \ \ \ \ \           30 \ bits}\\\\\\            = 2^7 \\\\ = 7 \ bits

calculating the register Bits:

= 64-(1+7+24+30)\\\\=64 -62\ \  bits\\\\= 2\ \ bits\\

C)

Immediate value size while merging the additional benefit with the address field:

= 2^{24} + 2^{30}\\\\= 2^{54}\\\\\texttt{Range before combining(-,+) 24 bits   \ \ \ \ \ \       Range after combining( -,+)54bits}\\\\                         \textt{-2^{12} from + (2^{12}-1)   \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \                                    -2^{27} from + (2^{27}- 1)}

= \frac{24}{2} = 12\\\\= \frac{54}{2} = 27

The range is accomplished by dividing the bits by 2 into the two sides of the o and the number is one short to 0.

8 0
3 years ago
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