First you put (x+5) into the initial function wherever you see x so it becomes
(x+5)^2+3(x+5)-10=x^2+kx+30
(x^2+5x+25)+(3x+15)-10 simplified left side
x^2+8x+30 fully simplified left side
thus k=8
x^2+8x+30=0 to find 0s
-4 + 3.7416573867739i
<span>-4 - 3.7416573867739i
</span>these are the roots you find after using the quadratic formula
the second one is the smallest
I belive it would be 12x + 12y
Answer:
(x,y)=(-2,-5)
Step-by-step explanation:
y=1/2x-4
y=-2x-9
(y=) 1/2x-4=-2x-9
1/2x +2x=-9+4
1/2x +4/2x=-5
5/2x=-5
5x=-5*2
5x=-10
x=-2
x=-2
y=-2x-9=-2*(-2)-9=4-9=-5
(x,y)=(-2,-5)
Answer:
<h2>x > 8</h2>
Step-by-step explanation:
= > -6x + 30 < - 18
= > 30 + 18 < 6x
= > 48 < 6x
= > x > 48/6
= > x > 8...ans
<h2>Hope it Helps you!! </h2>
