Answer:
equation of the circle J with center K(-7,3) and radius 6 is=
x^2+y^2+14x-6y+22=0
Step by step explanation:
Equation of circle with given centre (h,k) and radius r is
(x-h)^2+(y-k)^2=r^2
Given centre are K(-7,3) and radius 6.
So equation of Circle=
(x- -7)^2+(y-3)^2=6^2
x^2+14x+49+y^2-6y+9=36
x^2+y^2+14x-6y+22=0 answer
Answer:
d. √(1/(x+1))
Step-by-step explanation:
Just as operations can be performed on numbers and variables, so can operations be performed on functions. Here, you're asked to simplify the ratio of two functions.

At this point, you're supposed to know the factoring of the difference of squares:

You can write it in the form a^2 - b^2 where a = 5x and b = p
(5x)^2 - p^2
And then use the Difference of Squares a^2 - b^2 = (a + b)(a - b)
Answer is (5x + p)(5x - p)
A rhombus is a 4 sided shape with equal lengths. Even though it has equal lengths, it has opposite sides that are parallel, and angles that are equal. It also has diaginols (dashed lines) meat in the middle