Answer:
I will code in JAVA.
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
boolean tallEnough;
boolean oldEnough;
Scanner input = new Scanner(System.in);
tallEnough = input.nextBoolean();<em> //wait the input for tallEnough</em>
oldEnough = input.nextBoolean(); <em>//wait the input for OldEnough</em>
if(tallEnough && oldEnough){
System.out.print(true);
} else {
System.out.print(false);
}
}
}
Explanation:
First, to accept user inputs you have to import the class Scanner. Then declare both variables before allowing the user to set input values for both boolean variables.
In the if-else statement checks if both variables are true, then prints true. Another case prints always false.
Answer:
The correct answer to the following question will be Option D (Subtractive method
).
Explanation:
- This approach essentially requests a participant to construct two activities that are already in almost every way similar, except for a mental process that is assumed to also be included in any of the activities although omitted in another.
- This method will be much more valuable when deciding the period for phonemic awareness, despite text-string identification.
The other three options are not related to the given scenario. So that Option D is the right answer.
Answer:
Explanation:
Algorithm:
a. In each day, you will have to loop through the hotels that come to the hotel after you stayed last night.
b. If a hotel 'h' is found at more than 'd' distance away from last stayed hotel, then the hotel previous of 'h' is chosen to wait for that night. This is the greedy step, and you stay in this hotel.
c. The process for steps a and b is then repeated until we've reached the last hotel xn.
Running time:
Notice that the worst case occurs if each hotel is at a distance of successive multiples of 'd'. The best move is to estimate the distance to each hotel twice the whole computation in the scenario.
Thus, the total running time that could occur in the worst case is O(2n) = O(n). This is said to be linear time.
